[Solved] What is the output of the following MATLAB code?fullPath = fullfile('C:', 'Users', 'Documents', 'file.txt');[folder, name, ext] = fileparts(fullPath);disp(folder) | MATLAB

MATLAB - File I/O

What is the output of the following MATLAB code?

fullPath = fullfile('C:', 'Users', 'Documents', 'file.txt');
[folder, name, ext] = fileparts(fullPath);
disp(folder)

Afile.txt

BC:\Users\Documents

CC:/Users/Documents/file.txt

DDocuments

Step-by-Step Solution

Solution:

Step 1: Understand fullfile output
fullfile joins parts into a full path: 'C:\Users\Documents\file.txt' (Windows style).
Step 2: Use fileparts to split the path
fileparts splits into folder = 'C:\Users\Documents', name = 'file', ext = '.txt'.
Final Answer:
C:\Users\Documents -> Option B
Quick Check:
fileparts folder output = C:\Users\Documents [OK]

Quick Trick: fileparts(folder) excludes file name and extension [OK]

Common Mistakes:

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