Why control flow directs program logic in MATLAB - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if a number is positive.

MATLAB

if [1] > 0
    disp('Positive number');
end

Drag options to blanks, or click blank then click option'

Ax

Bvalue

Cnum

Dnumber

Attempts:

3 left

💡 Hint

Common Mistakes

Using a variable name not defined in the code.

The variable num is used to check if it is greater than zero.

2fill in blank

medium

Complete the code to execute the else block when the number is not positive.

MATLAB

if num > 0
    disp('Positive');
[1]
    disp('Not positive');
end

Drag options to blanks, or click blank then click option'

Aelseif num <= 0

Belseif

Cendif

Delse

Attempts:

3 left

💡 Hint

Common Mistakes

Using elseif without a condition.

The else keyword runs the code when the if condition is false.

3fill in blank

hard

Fix the error in the loop to print numbers from 1 to 5.

MATLAB

for i = 1:[1]
    disp(i);
end

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A5

B0

C6

D10

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0 or 6 as the upper limit.

The loop should run from 1 to 5, so the upper limit is 5.

4fill in blank

hard

Fill both blanks to create a loop that prints even numbers from 2 to 10.

MATLAB

for num = [1]:[2]:10
    disp(num);
end

Drag options to blanks, or click blank then click option'

A2

B1

D3

Attempts:

3 left

💡 Hint

Common Mistakes

Using 1 as the step value, which prints all numbers.

The loop starts at 2 and increments by 2 to print even numbers.

5fill in blank

hard

Fill all three blanks to create a conditional that prints 'Even' or 'Odd' for a number.

MATLAB

if mod([1], [2]) == [3]
    disp('Even');
else
    disp('Odd');
end

Drag options to blanks, or click blank then click option'

Anum

B2

C0

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using 1 as the remainder to check for even numbers.

The mod function checks if num divided by 2 has remainder 0 (even).