Bird
Raised Fist0
MATLABdata~5 mins

For loops in MATLAB - Cheat Sheet & Quick Revision

Choose your learning style10 modes available
Recall & Review
beginner
What is the basic syntax of a for loop in MATLAB?
The basic syntax is:
for index = startValue:endValue
    % code to repeat
end

This repeats the code for each value of index from startValue to endValue.
Click to reveal answer
beginner
How does a for loop in MATLAB differ from a while loop?

A for loop runs a fixed number of times, determined before the loop starts.

A while loop runs as long as a condition is true, which can change during execution.

Click to reveal answer
intermediate
What happens if the loop variable in a MATLAB for loop is a vector?
The loop runs once for each element in the vector, assigning the loop variable to that element each time.
Example:
for i = [2, 4, 6]
    disp(i)
end
prints 2, then 4, then 6.
Click to reveal answer
intermediate
Can you modify the loop variable inside a MATLAB for loop? What happens?
Modifying the loop variable inside the loop does not affect the next iteration.
MATLAB sets the loop variable to the next value in the sequence at the start of each iteration regardless of changes inside the loop.
Click to reveal answer
beginner
How do you exit a for loop early in MATLAB?
Use the break statement inside the loop.
When MATLAB encounters break, it stops the loop immediately and continues with the code after the loop.
Click to reveal answer
What does this MATLAB code print?
for i = 1:3
    disp(i)
end
AError
B3 2 1
C1 1 1
D1 2 3
In MATLAB, what happens if you write:
for i = [5 10 15]
    disp(i)
end
AIt prints 5, then 10, then 15
BIt prints 1 to 15
CIt prints only 15
DIt causes an error
What is the purpose of the break statement in a MATLAB for loop?
ATo skip the current iteration
BTo stop the loop immediately
CTo restart the loop
DTo pause the loop
If you change the loop variable inside a MATLAB for loop, what happens in the next iteration?
AThe loop variable resets to the next value in the sequence
BThe loop stops
CThe changed value is used
DAn error occurs
Which of these is a valid for loop header in MATLAB?
Afor i = 1 to 5
Bfor i in 1:5
Cfor i = 1:5
Dfor (i=1; i<=5; i++)
Explain how a for loop works in MATLAB and give an example.
Think about how the loop variable changes each time.
You got /4 concepts.
    Describe what happens if you modify the loop variable inside a MATLAB for loop.
    Consider how MATLAB controls the loop variable each iteration.
    You got /3 concepts.

      Practice

      (1/5)
      1. What does a for loop do in MATLAB?
      easy
      A. Stops the program immediately
      B. Runs commands only once
      C. Creates a new variable
      D. Repeats a set of commands a fixed number of times

      Solution

      1. Step 1: Understand the purpose of a for loop

        A for loop is designed to repeat commands multiple times based on a range or list.
      2. Step 2: Compare options with the definition

        Only Repeats a set of commands a fixed number of times correctly describes repeating commands a fixed number of times.
      3. Final Answer:

        Repeats a set of commands a fixed number of times -> Option D
      4. Quick Check:

        For loop = repeat commands [OK]
      Hint: For loops repeat commands multiple times [OK]
      Common Mistakes:
      • Thinking for loops run only once
      • Confusing for loops with if statements
      • Believing for loops stop the program
      2. Which of the following is the correct syntax for a for loop in MATLAB?
      easy
      A. for i = 1:5 disp(i) end
      B. for (i = 1; i <= 5; i++) disp(i) end
      C. loop i from 1 to 5 disp(i) end
      D. for i in range(1,5): disp(i)

      Solution

      1. Step 1: Identify MATLAB for loop syntax

        MATLAB uses 'for variable = start:end' and ends with 'end'.
      2. Step 2: Check each option

        for i = 1:5 disp(i) end matches MATLAB syntax. Options B, C, and D use other languages' syntax.
      3. Final Answer:

        for i = 1:5\n disp(i)\nend -> Option A
      4. Quick Check:

        MATLAB for loop = for i = 1:5 ... end [OK]
      Hint: MATLAB for loops use 'for var = start:end' and end with 'end' [OK]
      Common Mistakes:
      • Using parentheses like C or JavaScript
      • Using Python or other language syntax
      • Forgetting the 'end' keyword
      3. What is the output of this MATLAB code?
      sum = 0;
      for i = 1:3
        sum = sum + i;
      end
      disp(sum)
      medium
      A. 6
      B. 3
      C. 0
      D. Error

      Solution

      1. Step 1: Trace the loop iterations

        The loop runs i = 1, 2, 3. sum starts at 0.
      2. Step 2: Calculate sum after each iteration

        sum = 0+1=1, then 1+2=3, then 3+3=6.
      3. Final Answer:

        6 -> Option A
      4. Quick Check:

        1+2+3 = 6 [OK]
      Hint: Add numbers 1 to 3 inside loop [OK]
      Common Mistakes:
      • Forgetting to initialize sum
      • Adding outside the loop
      • Confusing loop range
      4. Identify the error in this MATLAB for loop:
      for i = 1:4
        disp(i)
        i = i + 1;
      end
      medium
      A. Missing 'end' keyword
      B. Modifying loop variable inside the loop
      C. Incorrect loop range syntax
      D. disp function is invalid

      Solution

      1. Step 1: Review loop variable usage

        The loop variable 'i' is controlled by MATLAB and should not be changed inside the loop.
      2. Step 2: Identify the problem

        Changing 'i' inside the loop causes unexpected behavior or errors.
      3. Final Answer:

        Modifying loop variable inside the loop -> Option B
      4. Quick Check:

        Do not change loop variable inside for loop [OK]
      Hint: Never change the loop variable inside the loop [OK]
      Common Mistakes:
      • Changing loop variable inside loop body
      • Forgetting 'end' keyword (not the case here)
      • Misunderstanding disp function
      5. How can you use a for loop in MATLAB to create a vector v containing squares of numbers from 1 to 5?
      hard
      A. v = []; for i = 1:5 v = v + i^2; end
      B. for i = 1:5 v(i) = i*2; end
      C. v = zeros(1,5); for i = 1:5 v(i) = i^2; end
      D. v = 1:5; for i = 1:5 v(i) = i + 2; end

      Solution

      1. Step 1: Initialize vector to store results

        Pre-allocate vector v with zeros to hold 5 elements.
      2. Step 2: Use for loop to assign squares

        For each i from 1 to 5, assign v(i) = i squared.
      3. Final Answer:

        v = zeros(1,5);\nfor i = 1:5\n v(i) = i^2;\nend -> Option C
      4. Quick Check:

        Pre-allocate vector and assign squares in loop [OK]
      Hint: Pre-allocate vector, assign squares inside loop [OK]
      Common Mistakes:
      • Not pre-allocating vector before loop
      • Adding instead of assigning inside loop
      • Using wrong operation for squares
      Recommended

      Ready to prove it?

      Pass the test and this pattern moves unknown strong while earning +1 Grip toward your certificate.

      10 questions~5 mineasy hard