Break and continue in MATLAB - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to exit the loop when the value reaches 5.

MATLAB

for i = 1:10
    if i == [1]
        break;
    end
end

Drag options to blanks, or click blank then click option'

A5

B0

C10

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Choosing a number outside the loop range.

Using continue instead of break.

The break statement stops the loop when i equals 5.

2fill in blank

medium

Complete the code to skip printing the number 3 using continue.

MATLAB

for i = 1:5
    if i == [1]
        continue;
    end
    disp(i)
end

Drag options to blanks, or click blank then click option'

A0

B1

C5

D3

Attempts:

3 left

💡 Hint

Common Mistakes

Using break instead of continue.

Choosing a number not in the loop range.

The continue statement skips the rest of the loop body when i is 3, so 3 is not printed.

3fill in blank

hard

Fix the error in the code to stop the loop when the sum exceeds 10.

MATLAB

sumVal = 0;
for i = 1:10
    sumVal = sumVal + i;
    if sumVal [1] 10
        break;
    end
end

Drag options to blanks, or click blank then click option'

A==

B>

C<

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using < or == which do not stop at the right time.

Not using a comparison operator.

The loop should stop when the sum is greater than 10, so use >.

4fill in blank

hard

Fill both blanks to create a loop that skips even numbers and stops at 7.

MATLAB

for i = 1:10
    if mod(i, 2) == [1]
        continue;
    end
    if i == [2]
        break;
    end
    disp(i)
end

Drag options to blanks, or click blank then click option'

A0

B1

C7

D5

Attempts:

3 left

💡 Hint

Common Mistakes

Using 1 instead of 0 for even check.

Stopping at the wrong number.

mod(i, 2) == 0 checks for even numbers to skip, and i == 7 stops the loop.

5fill in blank

hard

Fill all three blanks to print only odd numbers less than 10 and stop at 9.

MATLAB

for i = 1:15
    if mod(i, [1]) == [2]
        disp(i)
        if i == [3]
            break;
        end
    end
end

Drag options to blanks, or click blank then click option'

A2

B1

C9

D3

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0 instead of 1 for odd check.

Stopping at a number greater than 9.

The code checks for odd numbers with mod(i, 2) == 1 and stops when i == 9.