[Solved] Given the following pseudocode for notifying parties asynchronously, what is the expected output if notify prints "Notified {user}"?users = ["Ann", "Ben"] for user in users:... | LLD

LLD - Design — Food Delivery System

Given the following pseudocode for notifying parties asynchronously, what is the expected output if notify prints "Notified {user}"?

users = ["Ann", "Ben"]
for user in users:
    async_notify(user)
print("All notifications sent")

ANotified Ann Notified Ben All notifications sent

BAll notifications sent Notified Ann Notified Ben

CAll notifications sent

DNotified Ann All notifications sent Notified Ben

Step-by-Step Solution

Solution:

Step 1: Understand asynchronous calls behavior
Asynchronous calls start tasks but do not wait for them to finish immediately.
Step 2: Analyze the print order
The print statement runs immediately after starting async notifications, so "All notifications sent" prints first, then notifications complete and print their messages.
Final Answer:
All notifications sent Notified Ann Notified Ben -> Option B
Quick Check:
Async calls print after main flow [OK]

Quick Trick: Async calls don't block; main prints first [OK]

Common Mistakes:

MISTAKES

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Given the following pseudocode for notifying parties asynchronously, what is the expected output if notify prints "Notified {user}"?