[Solved] Consider this event-driven system snippet:events = [] def add_event(e): events.insert(0, e) def get_event(): if events: return events.... | LLD

LLD - Advanced LLD Concepts

Consider this event-driven system snippet:

events = []
def add_event(e):
    events.insert(0, e)
def get_event():
    if events:
        return events.pop()
    return None

add_event('X')
add_event('Y')
print(get_event())
print(get_event())

What is the output?

ANone None

BY X

CX Y

DY None

Step-by-Step Solution

Solution:

Step 1: Analyze event insertion
Events are inserted at the front: first 'X', then 'Y' at front, so list is ['Y', 'X'].
Step 2: Analyze event retrieval
get_event() pops from end, so first pop returns 'X', second pop returns 'Y'.
Final Answer:
X Y -> Option C
Quick Check:
Insert front, pop end = X Y [OK]

Quick Trick: Insert front + pop end reverses order [OK]

Common Mistakes:

Assuming pop removes front
Confusing insert and append
Mixing order of events

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Consider this event-driven system snippet:

Step 1: Analyze event insertion

Step 2: Analyze event retrieval

Final Answer:

Quick Check:

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