[Solved] Consider this simplified event-driven code snippet:event_queue = [] def produce(event): event_queue.append(event) def consume(): if event_queue: return event_queue.... | LLD

LLD - Advanced LLD Concepts

Consider this simplified event-driven code snippet:

event_queue = []

def produce(event):
    event_queue.append(event)

def consume():
    if event_queue:
        return event_queue.pop(0)
    return None

produce('A')
produce('B')
print(consume())
print(consume())
print(consume())

What is the output?

ANone None None

BB A None

CA B None

DA None B

Step-by-Step Solution

Solution:

Step 1: Trace event production
Two events 'A' and 'B' are added to the queue in order: ['A', 'B'].
Step 2: Trace event consumption
consume() removes and returns the first event: first 'A', then 'B', then None when empty.
Final Answer:
A B None -> Option C
Quick Check:
FIFO queue returns A then B then None [OK]

Quick Trick: Queue pops first-in event first (FIFO) [OK]

Common Mistakes:

MISTAKES

Assuming LIFO instead of FIFO
Forgetting to check empty queue
Mixing order of events

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Consider this simplified event-driven code snippet:

Step 1: Trace event production

Step 2: Trace event consumption

Final Answer:

Quick Check:

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