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Analyze the following pseudo-code for releasing a hold:

medium📝 Analysis Q4 of 15
LLD - Design — Library Management System
Analyze the following pseudo-code for releasing a hold:
if hold.exists(hold_id) and hold.is_expired(hold_id):
    release_hold(hold_id)
    return 'Hold released'
else:
    return 'Hold still valid'

What will be the output if the hold is still active?
A'Hold released'
B'Hold still valid'
C'Hold does not exist'
D'Error: Invalid hold_id'
Step-by-Step Solution
Solution:
  1. Step 1: Check hold existence

    The code first verifies if the hold exists using hold.exists(hold_id).
  2. Step 2: Check hold expiration

    Then it checks if the hold is expired with hold.is_expired(hold_id).
  3. Step 3: Evaluate condition when hold is active

    If the hold is still active (not expired), the condition fails, so the else branch executes.
  4. Final Answer:

    'Hold still valid' -> Option B
  5. Quick Check:

    Hold active means no release triggered [OK]
Quick Trick: If hold not expired, else branch runs [OK]
Common Mistakes:
MISTAKES
  • Assuming expired hold returns 'Hold still valid'
  • Confusing hold existence with expiration status
  • Ignoring the else branch in conditional logic

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