| Users / Requests | What Changes? |
|---|---|
| 100 requests/sec | Single chain instance handles requests sequentially; low latency; simple setup. |
| 10,000 requests/sec | Chain instances may become CPU-bound; latency increases; need parallel chains or load balancing. |
| 1,000,000 requests/sec | Single server insufficient; multiple servers with replicated chains; distributed load balancing required. |
| 100,000,000 requests/sec | Global distributed system; chains partitioned by request type; caching and asynchronous processing essential. |
Chain of Responsibility pattern in LLD - Scalability & System Analysis
Start learning this pattern below
Jump into concepts and practice - no test required
The first bottleneck is the processing capacity of the chain handlers. As requests increase, the sequential nature of the chain causes delays because each handler must process or pass the request. CPU and memory limits on the server running the chain break first.
- Horizontal scaling: Run multiple chain instances on different servers to share load.
- Load balancing: Distribute incoming requests evenly across chain instances.
- Parallel chains: Partition requests by type or category so different chains handle different requests.
- Caching: Cache results of handlers that produce repeatable outputs to avoid redundant processing.
- Asynchronous processing: Use queues to decouple request reception from processing, smoothing spikes.
- At 10,000 requests/sec, assuming each handler takes 1ms, a single chain can handle ~1000 requests/sec; need ~10 servers.
- Storage is minimal unless handlers log extensively; estimate 1KB per request -> 10MB/sec at 10K req/sec.
- Network bandwidth depends on request/response size; for 1KB each, 10MB/sec inbound and outbound at 10K req/sec.
Start by explaining the chain's sequential processing and its impact on latency. Identify the handler processing as the bottleneck. Then discuss horizontal scaling and load balancing. Mention caching and asynchronous queues as optimizations. Always relate solutions to the bottleneck you identified.
Your chain handles 1000 requests per second. Traffic grows 10x to 10,000 requests per second. What do you do first?
Answer: Add more chain instances and use load balancing to distribute requests, because a single chain cannot process 10,000 requests per second sequentially.
Practice
Chain of Responsibility pattern in system design?Solution
Step 1: Understand the pattern's behavior
The Chain of Responsibility pattern allows a request to be passed along a chain of objects until one can handle it.Step 2: Compare options with the pattern's purpose
The options describing singleton (one instance), prototype (object copies), and strategy (interchangeable algorithms) refer to other design patterns, not Chain of Responsibility.Final Answer:
To pass a request along a chain of handlers until one handles it -> Option AQuick Check:
Chain of Responsibility = pass request along chain [OK]
- Confusing with Singleton or Strategy patterns
- Thinking it creates object copies
- Assuming it handles all requests at once
Solution
Step 1: Recall how handlers are connected
In Chain of Responsibility, each handler has a reference to the next handler to pass the request along.Step 2: Evaluate other options
Global static lists, shared databases, and independent handlers describe unrelated or incorrect linking methods that contradict the chain concept.Final Answer:
Each handler holds a reference to the next handler in the chain -> Option DQuick Check:
Handler links = next handler reference [OK]
- Using global lists instead of direct references
- Assuming handlers are independent
- Confusing with event broadcasting
class Handler:
def __init__(self, successor=None):
self.successor = successor
def handle(self, request):
if self.can_handle(request):
return f"Handled {request}"
elif self.successor:
return self.successor.handle(request)
else:
return "Not handled"
def can_handle(self, request):
return False
class ConcreteHandlerA(Handler):
def can_handle(self, request):
return request == 'A'
class ConcreteHandlerB(Handler):
def can_handle(self, request):
return request == 'B'
chain = ConcreteHandlerA(ConcreteHandlerB())
print(chain.handle('B'))What is the output of this code?
Solution
Step 1: Trace the request through the chain
The request 'B' is first checked by ConcreteHandlerA, which returns False for can_handle('B'). It passes the request to ConcreteHandlerB.Step 2: ConcreteHandlerB handles the request
ConcreteHandlerB's can_handle('B') returns True, so it returns "Handled B".Final Answer:
Handled B -> Option AQuick Check:
Request 'B' handled by second handler [OK]
- Assuming first handler handles all requests
- Confusing return values
- Missing the chain passing logic
class Handler:
def __init__(self, successor=None):
self.successor = successor
def handle(self, request):
if self.can_handle(request):
return f"Handled {request}"
else:
return "Not handled"
def can_handle(self, request):
return False
class ConcreteHandler(Handler):
def can_handle(self, request):
return request == 'X'
chain = ConcreteHandler()
print(chain.handle('Y'))What is the main issue here?
Solution
Step 1: Analyze the handle method logic
The handle method checks can_handle; if False, it returns "Not handled" immediately without passing to successor.Step 2: Identify missing chain passing
It should call self.successor.handle(request) if successor exists, but this is missing.Final Answer:
The handler does not pass the request to the successor -> Option CQuick Check:
Missing successor call breaks chain [OK]
- Forgetting to call successor.handle()
- Assuming can_handle always returns True
- Ignoring successor initialization
Solution
Step 1: Understand the logging severity flow
Logs should be handled at their level, and higher severity logs should continue down the chain for further handling.Step 2: Evaluate options for correct chain behavior
Each handler processes logs at its level and passes only higher severity logs to the next handler matches this: handlers process their level and pass higher severity logs onward. Each handler processes only its level and passes all logs to the next handler passes all logs regardless, which is inefficient. Each handler processes all logs regardless of severity and stops the chain stops chain prematurely. Each handler processes logs randomly without order is random and incorrect.Final Answer:
Each handler processes logs at its level and passes only higher severity logs to the next handler -> Option BQuick Check:
Process level, pass higher severity [OK]
- Passing all logs without filtering
- Stopping chain too early
- Ignoring severity order
