Bird
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LLDsystem_design~3 mins

Why SOLID violations and fixes in LLD? - Purpose & Use Cases

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The Big Idea

What if your code could change as easily as swapping LEGO blocks without breaking everything?

The Scenario

Imagine building a big LEGO castle where every piece is glued together. If you want to change a tower or add a new room, you have to break the glue and risk damaging the whole castle.

The Problem

When code breaks SOLID principles, it becomes like that glued LEGO castle. Making changes is slow, risky, and causes unexpected bugs because parts are tightly connected and hard to fix or replace.

The Solution

SOLID principles guide us to build code like LEGO blocks that snap together but can be taken apart easily. This makes the system flexible, easier to understand, and safer to change without breaking other parts.

Before vs After
✗ Before
class OrderProcessor {
  void process(Order order) {
    // process payment
    // update inventory
    // send confirmation email
  }
}
✓ After
interface PaymentService { void pay(Order order); }
interface InventoryService { void update(Order order); }
interface NotificationService { void notify(Order order); }

class OrderProcessor {
  PaymentService payment;
  InventoryService inventory;
  NotificationService notification;

  void process(Order order) {
    payment.pay(order);
    inventory.update(order);
    notification.notify(order);
  }
}
What It Enables

It enables building software that adapts easily to new needs without breaking existing features.

Real Life Example

Think of a smartphone app where you can add new features like payment methods or notifications without rewriting the whole app.

Key Takeaways

SOLID helps keep code flexible and maintainable.

It reduces bugs when making changes.

It makes teamwork easier by separating responsibilities.

Practice

(1/5)
1. Which SOLID principle is violated if a class has too many responsibilities, making it hard to maintain?
easy
A. Single Responsibility Principle
B. Open/Closed Principle
C. Liskov Substitution Principle
D. Interface Segregation Principle

Solution

  1. Step 1: Understand the problem of multiple responsibilities

    A class with many responsibilities is hard to maintain and change because changes in one responsibility may affect others.
  2. Step 2: Identify the violated SOLID principle

    The Single Responsibility Principle states that a class should have only one reason to change, meaning one responsibility.
  3. Final Answer:

    Single Responsibility Principle -> Option A
  4. Quick Check:

    One class, one responsibility = C [OK]
Hint: One class, one job means Single Responsibility Principle [OK]
Common Mistakes:
  • Confusing Single Responsibility with Open/Closed Principle
  • Thinking Liskov Substitution relates to responsibilities
  • Mixing Interface Segregation with class responsibilities
2. Which of the following code snippets correctly applies the Open/Closed Principle by allowing extension without modification?
class Shape {
draw() { /* draw shape */ }
}
class Circle extends Shape {
draw() { /* draw circle */ }
}
easy
A. Adding new shape classes by extending Shape without changing existing code
B. Modifying the Shape class draw method to handle all shapes
C. Using a single class for all shapes with if-else inside draw
D. Changing Circle class to override Shape's draw method with new logic

Solution

  1. Step 1: Understand Open/Closed Principle

    This principle says software entities should be open for extension but closed for modification.
  2. Step 2: Analyze the code snippet

    Extending Shape with new classes like Circle adds new behavior without changing existing Shape code.
  3. Final Answer:

    Adding new shape classes by extending Shape without changing existing code -> Option A
  4. Quick Check:

    Extend without modify = A [OK]
Hint: Extend classes, don't change existing ones [OK]
Common Mistakes:
  • Modifying base class instead of extending
  • Using if-else inside methods to handle new cases
  • Overriding methods incorrectly causing side effects
3. Given the following code violating Interface Segregation Principle, what is the output when calling robot.work()?
interface Worker {
void work();
void eat();
}
class Robot implements Worker {
public void work() { System.out.println("Robot working"); }
public void eat() { throw new UnsupportedOperationException(); }
}
Robot robot = new Robot();
robot.work();
medium
A. No output
B. UnsupportedOperationException thrown
C. Compilation error
D. Robot working

Solution

  1. Step 1: Understand the code behavior

    The robot class implements work() by printing "Robot working" and eat() throws an exception.
  2. Step 2: Analyze the method called

    Only robot.work() is called, which prints the message without error.
  3. Final Answer:

    Robot working -> Option D
  4. Quick Check:

    Calling work() prints message = A [OK]
Hint: Calling only implemented methods avoids exceptions [OK]
Common Mistakes:
  • Assuming eat() is called causing exception
  • Thinking interface violation causes compile error
  • Ignoring method actually called in code
4. Identify the main problem in this code violating Liskov Substitution Principle:
class Bird {
void fly() { System.out.println("Flying"); }
}
class Ostrich extends Bird {
void fly() { throw new UnsupportedOperationException(); }
}
medium
A. Bird class should not have fly method
B. Ostrich should override fly with different signature
C. Ostrich cannot replace Bird without breaking behavior
D. No violation, code is correct

Solution

  1. Step 1: Understand Liskov Substitution Principle

    Subtypes must be replaceable for their base types without altering correctness.
  2. Step 2: Analyze Ostrich behavior

    Ostrich throws exception on fly(), breaking expected behavior of Bird.
  3. Final Answer:

    Ostrich cannot replace Bird without breaking behavior -> Option C
  4. Quick Check:

    Subtype must behave like base = B [OK]
Hint: Subtype must not break base class behavior [OK]
Common Mistakes:
  • Thinking method signature change fixes violation
  • Ignoring exception breaking substitution
  • Assuming base class design is wrong here
5. You have a payment system where the PaymentProcessor interface has methods payWithCreditCard(), payWithPayPal(), and payWithCrypto(). A new payment method is added, but many classes implementing this interface do not support all methods, causing empty or error implementations. How should you fix this design following SOLID principles?
hard
A. Remove unsupported methods from implementations silently
B. Split the interface into smaller ones for each payment method
C. Keep one interface and add flags to check supported methods
D. Add default empty implementations to the interface methods

Solution

  1. Step 1: Identify the violated principle

    Having one interface with many methods causes classes to implement unsupported methods, violating Interface Segregation Principle.
  2. Step 2: Apply the fix

    Splitting the interface into smaller, specific interfaces lets classes implement only what they support, improving design.
  3. Final Answer:

    Split the interface into smaller ones for each payment method -> Option B
  4. Quick Check:

    Small interfaces, no unused methods = D [OK]
Hint: Use many small interfaces, not one big one [OK]
Common Mistakes:
  • Adding empty default methods hides design flaws
  • Using flags complicates code and violates design
  • Removing methods silently breaks interface contract
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10 questions~5 mineasy hard