[Solved] What will be the output of this code? cache = InMemoryCache() cache.get_or_set('a', lambda: 'hello') cache.get_or_set('b', lambda: 'world') print(cache.get_or_set('a', lambda: 'new')) | LangChain

LangChain - Production Deployment

What will be the output of this code?

cache = InMemoryCache()
cache.get_or_set('a', lambda: 'hello')
cache.get_or_set('b', lambda: 'world')
print(cache.get_or_set('a', lambda: 'new'))

Aworld

Bnew

Chello

DError

Step-by-Step Solution

Solution:

Step 1: Cache stores 'hello' under key 'a'
First call caches 'hello' for 'a'.
Step 2: Second call caches 'world' under 'b'
Third call returns cached 'hello' for 'a', ignoring lambda.
Final Answer:
hello -> Option C
Quick Check:
Cache returns first stored value for key [OK]

Quick Trick: Cache returns original stored value for repeated keys [OK]

Common Mistakes:

MISTAKES

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What will be the output of this code?