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LangChainframework~10 mins

Parallel execution with RunnableParallel in LangChain - Interactive Code Practice

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Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to create a RunnableParallel instance with two runnables.

LangChain
from langchain.schema.runnable import Runnable
from langchain.schema.runnable.parallel import RunnableParallel

runnable1 = Runnable()
runnable2 = Runnable()
parallel = RunnableParallel([1])
Drag options to blanks, or click blank then click option'
Arunnable1, runnable2
Brunnable1=runnable1, runnable2=runnable2
C(runnable1, runnable2)
D{runnable1, runnable2}
Attempts:
3 left
💡 Hint
Common Mistakes
Using square brackets for list syntax.
Passing runnables separated by commas without keyword names.
2fill in blank
medium

Complete the code to run the RunnableParallel instance with input 'data'.

LangChain
result = parallel.[1]('data')
Drag options to blanks, or click blank then click option'
Aexecute
Brun
Cinvoke
Dinvoke_async
Attempts:
3 left
💡 Hint
Common Mistakes
Using 'run' or 'execute' which are not methods of RunnableParallel.
Using 'invoke_async' which is for asynchronous calls.
3fill in blank
hard

Fix the error in the code to run RunnableParallel asynchronously.

LangChain
import asyncio

async def main():
    result = await parallel.[1]('input')
    print(result)

asyncio.run(main())
Drag options to blanks, or click blank then click option'
Aainvoke
Brun
Cexecute_async
Dasync_run
Attempts:
3 left
💡 Hint
Common Mistakes
Using synchronous methods with await causing errors.
Using method names that do not exist in RunnableParallel.
4fill in blank
hard

Fill both blanks to create a RunnableParallel that runs two different runnables and run it synchronously.

LangChain
r1 = Runnable()
r2 = Runnable()
parallel = RunnableParallel([1]=r1, [2]=r2)
output = parallel.[3]('test input')
Drag options to blanks, or click blank then click option'
Ar1
Br2
Cinvoke
Dexecute
Attempts:
3 left
💡 Hint
Common Mistakes
Passing runnables without kwarg syntax or with wrong syntax.
Using 'execute' which is not a RunnableParallel method.
5fill in blank
hard

Fill all three blanks to create a RunnableParallel, run it asynchronously, and print the result.

LangChain
import asyncio

r1 = Runnable()
r2 = Runnable()
parallel = RunnableParallel([1]=r1, [2]=r2)

async def main():
    result = await parallel.[3]('async input')
    print(result)

asyncio.run(main())
Drag options to blanks, or click blank then click option'
Ar1
Br2
Cainvoke
Drun
Attempts:
3 left
💡 Hint
Common Mistakes
Using synchronous invoke method with await causing errors.
Passing runnables without kwarg syntax.

Practice

(1/5)
1. What is the main purpose of using RunnableParallel in langchain?
easy
A. To run multiple tasks at the same time to save time
B. To run tasks one after another in a fixed order
C. To stop tasks from running automatically
D. To run only one task repeatedly

Solution

  1. Step 1: Understand RunnableParallel's role

    RunnableParallel is designed to run tasks together, not sequentially.
  2. Step 2: Identify the benefit

    Running tasks in parallel saves time by doing them simultaneously.
  3. Final Answer:

    To run multiple tasks at the same time to save time -> Option A
  4. Quick Check:

    Parallel execution = run tasks together [OK]
Hint: RunnableParallel means tasks run together, not one by one [OK]
Common Mistakes:
  • Thinking RunnableParallel runs tasks one after another
  • Confusing parallel with repeated single task
  • Assuming it stops tasks automatically
2. Which of the following is the correct way to create a RunnableParallel with two tasks named task1 and task2?
easy
A. RunnableParallel{task1, task2}
B. RunnableParallel(task1, task2)
C. RunnableParallel({"task1": task1, "task2": task2})
D. RunnableParallel(task1 + task2)

Solution

  1. Step 1: Recall RunnableParallel syntax

    RunnableParallel expects a dictionary {"name": task} as its argument.
  2. Step 2: Match options to syntax

    Only RunnableParallel({"task1": task1, "task2": task2}) passes a dict {"task1": task1, "task2": task2}, others use wrong syntax.
  3. Final Answer:

    RunnableParallel({"task1": task1, "task2": task2}) -> Option C
  4. Quick Check:

    Dict of tasks = {"task1": task1, "task2": task2} [OK]
Hint: Use curly braces {} to pass {"name": task} dictionary [OK]
Common Mistakes:
  • Passing tasks as separate positional arguments
  • Using invalid set syntax {}
  • Trying to add tasks with + operator
3. Given the code:
parallel = RunnableParallel({"taskA": taskA, "taskB": taskB})
results = parallel.invoke()
print(results)

If taskA returns 'Hello' and taskB returns 'World', what will be printed?
medium
A. {'taskB': 'World', 'taskA': 'Hello'}
B. ['HelloWorld']
C. 'Hello World'
D. {'taskA': 'Hello', 'taskB': 'World'}

Solution

  1. Step 1: Understand RunnableParallel output order

    RunnableParallel returns a dict with results in the order keys are defined.
  2. Step 2: Match task results to output dict

    taskA under 'taskA' returns 'Hello' first, taskB under 'taskB' returns 'World' second, so {'taskA': 'Hello', 'taskB': 'World'}.
  3. Final Answer:

    {'taskA': 'Hello', 'taskB': 'World'} -> Option D
  4. Quick Check:

    Order of results matches dict definition order [OK]
Hint: Results dict order matches task definition order [OK]
Common Mistakes:
  • Reversing the order of task results
  • Thinking results are combined into one string
  • Expecting a list instead of dict output
4. What is wrong with this code snippet?
parallel = RunnableParallel(task1, task2)
results = parallel.invoke()
medium
A. RunnableParallel requires tasks inside a dictionary, not separate arguments
B. invoke() method does not exist on RunnableParallel
C. You must call run() instead of invoke()
D. RunnableParallel cannot run more than one task

Solution

  1. Step 1: Check RunnableParallel constructor usage

    RunnableParallel expects a dictionary of tasks, not separate positional arguments.
  2. Step 2: Identify the error in code

    Passing task1, task2 as separate positional arguments causes a TypeError.
  3. Final Answer:

    RunnableParallel requires tasks inside a dictionary, not separate arguments -> Option A
  4. Quick Check:

    Tasks must be in a dictionary [OK]
Hint: Always use a dictionary or named kwargs for RunnableParallel tasks [OK]
Common Mistakes:
  • Passing tasks as separate positional arguments
  • Using wrong method name instead of invoke()
  • Thinking RunnableParallel runs only one task
5. You want to run three independent tasks taskX, taskY, and taskZ in parallel and combine their results into a single string separated by commas. Which code correctly does this?
hard
A. parallel = RunnableParallel(taskX, taskY, taskZ) results = parallel.invoke() combined = ','.join(results) print(combined)
B. parallel = RunnableParallel({"taskX": taskX, "taskY": taskY, "taskZ": taskZ}) results = parallel.invoke() combined = ','.join(results.values()) print(combined)
C. results = [taskX(), taskY(), taskZ()] combined = ','.join(results) print(combined)
D. parallel = RunnableParallel([taskX, taskY, taskZ]) combined = parallel.invoke().join(',') print(combined)

Solution

  1. Step 1: Create RunnableParallel with dictionary of tasks

    parallel = RunnableParallel({"taskX": taskX, "taskY": taskY, "taskZ": taskZ}) results = parallel.invoke() combined = ','.join(results.values()) print(combined) correctly passes tasks as a dictionary to RunnableParallel.
  2. Step 2: Invoke and join results properly

    This calls invoke() to get dict results, then joins the values with commas correctly.
  3. Step 3: Check other options for errors

    parallel = RunnableParallel(taskX, taskY, taskZ) results = parallel.invoke() combined = ','.join(results) print(combined) passes tasks incorrectly as positional; C runs tasks sequentially; D uses invalid list and misuses join.
  4. Final Answer:

    Using RunnableParallel({"taskX": taskX, "taskY": taskY, "taskZ": taskZ}) and ','.join(results.values()) -> Option B
  5. Quick Check:

    Dict tasks + invoke + join values = correct [OK]
Hint: Pass tasks as dict, invoke, then ','.join(results.values()) [OK]
Common Mistakes:
  • Passing tasks without dictionary syntax
  • Calling join() on the wrong object
  • Running tasks sequentially instead of parallel