[Solved] Identify the error in this Kotlin code snippet: outer@ for (i in 1..2) { for (j in 1..2) { if (i == 1) continue outer println("i=$i, j=$j") } } | Kotlin

Kotlin - Loops and Ranges

Identify the error in this Kotlin code snippet:

outer@ for (i in 1..2) {
    for (j in 1..2) {
        if (i == 1) continue outer
        println("i=$i, j=$j")
    }
}

Acontinue@outer should be used instead of continue outer.

Bcontinue cannot be used with a label on an inner loop.

CLabel 'outer' is not defined.

DNo error; code runs correctly.

Step-by-Step Solution

Solution:

Step 1: Check labeled continue syntax
Kotlin requires the @ symbol when using labels with break or continue, so it must be continue@outer.
Step 2: Verify label definition and usage
The label 'outer' is correctly defined, so Label 'outer' is not defined. is wrong. Using continue with label without @ causes syntax error.
Final Answer:
continue@outer should be used instead of continue outer. -> Option A
Quick Check:
Use continue@label syntax to avoid errors [OK]

Quick Trick: Always use @ with label in continue or break [OK]

Common Mistakes:

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