[Solved] Given a list of mixed types val items: List = listOf(3, "Hi", 7, "Bye", 10), write a Kotlin when expression inside a loop to print "Number in range" if the item is an Int in 1..... | Kotlin

Kotlin - Control Flow as Expressions

Given a list of mixed types val items: List = listOf(3, "Hi", 7, "Bye", 10), write a Kotlin when expression inside a loop to print "Number in range" if the item is an Int in 1..5, "Number out of range" if Int but not in 1..5, and "Text found" if the item is a String. What will be printed?

A"Text found", "Number in range", "Text found", "Number out of range", "Number in range"

B"Number in range", "Text found", "Number out of range", "Text found", "Number out of range"

C"Number in range", "Text found", "Number in range", "Text found", "Number out of range"

D"Number out of range", "Text found", "Number in range", "Text found", "Number in range"

Step-by-Step Solution

Solution:

Step 1: Analyze each item and apply conditions
3 is Int in 1..5 -> "Number in range"; "Hi" is String -> "Text found"; 7 is Int not in 1..5 -> "Number out of range"; "Bye" is String -> "Text found"; 10 is Int not in 1..5 -> "Number out of range".
Step 2: List outputs in order
Outputs are: "Number in range", "Text found", "Number out of range", "Text found", "Number out of range".
Final Answer:
"Number in range", "Text found", "Number out of range", "Text found", "Number out of range" -> Option B
Quick Check:
Check type and range per item in loop = D [OK]

Quick Trick: Check type first, then range inside when branches [OK]

Common Mistakes:

MISTAKES

Mixing up range boundaries
Ignoring type before range check
Misordering output sequence

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What will be printed?

Step 1: Analyze each item and apply conditions

Step 2: List outputs in order

Final Answer:

Quick Check:

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