Why producers publish data in Kafka - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to send a message to a Kafka topic.

Kafka

producer.send('[1]', b'Hello World')

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Amy_topic

Bconsumer_group

Cbroker_list

Dpartition_key

Attempts:

3 left

💡 Hint

Common Mistakes

Using consumer group or broker list instead of topic name.

The producer must specify the topic name where the data will be published. Here, my_topic is the correct topic.

2fill in blank

medium

Complete the code to create a Kafka producer with the correct bootstrap server.

Kafka

producer = KafkaProducer(bootstrap_servers='[1]')

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Alocalhost:9092

Bconsumer_group:9092

Ctopic_name:9092

Dpartition_key:9092

Attempts:

3 left

💡 Hint

Common Mistakes

Using consumer group or topic name instead of broker address.

The bootstrap_servers parameter must point to the Kafka broker address, usually localhost:9092 for local setups.

3fill in blank

hard

Fix the error in the code to publish a message with a key.

Kafka

producer.send('my_topic', key=[1], value=b'Hello')

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A'key1'

Bkey1

Cb'key1'

DNone

Attempts:

3 left

💡 Hint

Common Mistakes

Using string keys without bytes prefix.

The key must be bytes, so b'key1' is correct. Using a string without b'' causes an error.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps words to their lengths only if length is greater than 3.

Kafka

{word: [1] for word in words if [2]

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Alen(word)

Bword > 3

Clen(word) > 3

Dword

Attempts:

3 left

💡 Hint

Common Mistakes

Using the word itself as value or wrong condition syntax.

The dictionary maps each word to its length using len(word). The condition filters words with length greater than 3 using len(word) > 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase keys to values only if value is positive.

Kafka

result = [1]: [2] for [3], [2] in data.items() if [2] > 0

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Ak.upper()

Bv

Ck

Dvalue

Attempts:

3 left

💡 Hint

Common Mistakes

Using wrong variable names or not converting keys to uppercase.

The keys are converted to uppercase with k.upper(). The values are v. The loop variables are k and v. The condition filters positive values.