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JUnittesting~10 mins

assertThrows for exceptions in JUnit - Test Execution Trace

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Test Overview

This test checks that a method throws the expected exception when given invalid input. It verifies that the exception type and message are correct.

Test Code - JUnit 5
JUnit
import static org.junit.jupiter.api.Assertions.assertThrows;
import static org.junit.jupiter.api.Assertions.assertEquals;
import org.junit.jupiter.api.Test;

class Calculator {
    int divide(int a, int b) {
        if (b == 0) {
            throw new IllegalArgumentException("Divider cannot be zero");
        }
        return a / b;
    }
}

public class CalculatorTest {
    @Test
    void testDivideByZeroThrowsException() {
        Calculator calc = new Calculator();
        IllegalArgumentException exception = assertThrows(IllegalArgumentException.class, () -> {
            calc.divide(10, 0);
        });
        assertEquals("Divider cannot be zero", exception.getMessage());
    }
}
Execution Trace - 5 Steps
StepActionSystem StateAssertionResult
1Test startsJUnit test runner initialized—PASS
2Calculator object createdCalculator instance ready—PASS
3assertThrows called with IllegalArgumentException.class and lambda calling divide(10, 0)Executing divide method with b=0Exception of type IllegalArgumentException is thrownPASS
4Exception caught by assertThrows and storedException message: 'Divider cannot be zero'Exception message equals 'Divider cannot be zero'PASS
5Test ends successfullyTest passed with expected exception—PASS
Failure Scenario
Failing Condition: divide method does not throw IllegalArgumentException when dividing by zero
Execution Trace Quiz - 3 Questions
Test your understanding
What does assertThrows verify in this test?
AThat the divide method does not throw any exception
BThat the divide method returns zero when dividing by zero
CThat the divide method throws IllegalArgumentException when dividing by zero
DThat the divide method throws NullPointerException
Key Result
Use assertThrows to verify that your code throws the correct exception type and then check the exception message to ensure the error is exactly what you expect.

Practice

(1/5)
1. What is the main purpose of assertThrows in JUnit testing?
easy
A. To check if a specific exception is thrown by a block of code
B. To verify the return value of a method
C. To measure the execution time of a method
D. To skip a test case conditionally

Solution

  1. Step 1: Understand the role of assertThrows

    assertThrows is designed to check if a certain exception occurs when running some code.
  2. Step 2: Compare with other options

    Options B, C, and D describe different test functions unrelated to exception checking.
  3. Final Answer:

    To check if a specific exception is thrown by a block of code -> Option A
  4. Quick Check:

    assertThrows checks exceptions = A [OK]
Hint: Remember: assertThrows tests exceptions thrown by code [OK]
Common Mistakes:
  • Confusing assertThrows with assertEquals
  • Thinking assertThrows measures performance
  • Using assertThrows to skip tests
2. Which of the following is the correct syntax to use assertThrows in JUnit 5?
easy
A. assertThrows(Exception.class, () -> methodCall());
B. assertThrows(() -> methodCall(), Exception.class);
C. assertThrows(methodCall(), Exception.class);
D. assertThrows(Exception.class, methodCall());

Solution

  1. Step 1: Recall the method signature

    The correct syntax is assertThrows(Exception.class, executable) where executable is a lambda or method reference.
  2. Step 2: Check each option

    assertThrows(Exception.class, () -> methodCall()); matches the correct order and lambda usage. Options A, B, and D have wrong argument order or missing lambda.
  3. Final Answer:

    assertThrows(Exception.class, () -> methodCall()); -> Option A
  4. Quick Check:

    Exception class first, then lambda = C [OK]
Hint: Exception class first, then lambda with code [OK]
Common Mistakes:
  • Swapping the order of arguments
  • Passing method call instead of lambda
  • Omitting the lambda expression
3. What will be the result of this JUnit test?
import static org.junit.jupiter.api.Assertions.assertThrows;

@Test
void testDivideByZero() {
  assertThrows(ArithmeticException.class, () -> {
    int result = 10 / 0;
  });
}
medium
A. Test passes but exception type is wrong
B. Test fails because no exception is thrown
C. Test fails due to syntax error
D. Test passes because ArithmeticException is thrown

Solution

  1. Step 1: Analyze the code inside assertThrows

    The code divides 10 by 0, which throws an ArithmeticException at runtime.
  2. Step 2: Check if exception matches expected

    assertThrows expects ArithmeticException.class, which matches the thrown exception.
  3. Final Answer:

    Test passes because ArithmeticException is thrown -> Option D
  4. Quick Check:

    Exception thrown matches expected = A [OK]
Hint: Divide by zero throws ArithmeticException [OK]
Common Mistakes:
  • Assuming no exception is thrown
  • Confusing exception types
  • Thinking test fails on exception
4. Identify the error in this JUnit test using assertThrows:
@Test
void testNullPointer() {
  assertThrows(NullPointerException, () -> {
    String s = null;
    s.length();
  });
}
medium
A. Lambda syntax is incorrect
B. NullPointerException is not thrown here
C. Missing .class after NullPointerException
D. assertThrows cannot test NullPointerException

Solution

  1. Step 1: Check the exception argument

    The exception class must be passed as NullPointerException.class, not just the class name.
  2. Step 2: Verify lambda and exception thrown

    The lambda syntax is correct and the code throws NullPointerException as expected.
  3. Final Answer:

    Missing .class after NullPointerException -> Option C
  4. Quick Check:

    Exception class needs .class suffix = B [OK]
Hint: Always add .class after exception name in assertThrows [OK]
Common Mistakes:
  • Omitting .class after exception
  • Miswriting lambda syntax
  • Assuming exception not thrown
5. You want to test that a method parseNumber(String s) throws NumberFormatException only when the input is not a valid number. Which of these tests correctly uses assertThrows to check this behavior?
hard
A. assertThrows(NumberFormatException.class, () -> parseNumber(123));
B. assertThrows(NumberFormatException.class, () -> parseNumber("abc"));
C. assertThrows(Exception.class, () -> parseNumber(null));
D. assertThrows(NumberFormatException.class, () -> parseNumber("123"));

Solution

  1. Step 1: Understand the method behavior

    parseNumber should throw NumberFormatException for invalid strings like "abc" but not for valid numbers like "123".
  2. Step 2: Evaluate each test case

    assertThrows(NumberFormatException.class, () -> parseNumber("abc")); tests invalid input "abc" correctly. assertThrows(NumberFormatException.class, () -> parseNumber("123")); tests valid input, so no exception expected. assertThrows(Exception.class, () -> parseNumber(null)); uses a different exception and null input. assertThrows(NumberFormatException.class, () -> parseNumber(123)); passes an integer instead of string, causing compile error.
  3. Final Answer:

    assertThrows(NumberFormatException.class, () -> parseNumber("abc")); -> Option B
  4. Quick Check:

    Test invalid input throws NumberFormatException = D [OK]
Hint: Test invalid strings with assertThrows for NumberFormatException [OK]
Common Mistakes:
  • Testing valid input expecting exception
  • Passing wrong argument types
  • Using wrong exception class
Recommended

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10 questions~5 mineasy hard