Jenkinsfile per branch - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to checkout the current branch in Jenkins pipeline.

Jenkins

checkout([$class: 'GitSCM', branches: [[name: '[1]']], userRemoteConfigs: [[url: 'https://github.com/example/repo.git']]])

Drag options to blanks, or click blank then click option'

Amain

Bmaster

Cenv.BRANCH_NAME

Ddevelop

Attempts:

3 left

💡 Hint

Common Mistakes

Hardcoding branch name instead of using environment variable.

Using incorrect variable names.

Using env.BRANCH_NAME dynamically checks out the current branch in Jenkins pipeline.

2fill in blank

medium

Complete the code to select the Jenkinsfile path based on the branch name.

Jenkins

def jenkinsfilePath = (env.BRANCH_NAME == 'main') ? '[1]' : 'Jenkinsfile.dev'

Drag options to blanks, or click blank then click option'

AJenkinsfile

BJenkinsfile.main

CJenkinsfile.prod

DJenkinsfile.master

Attempts:

3 left

💡 Hint

Common Mistakes

Using incorrect Jenkinsfile names.

Confusing branch names with Jenkinsfile names.

The default Jenkinsfile is usually named Jenkinsfile. For the main branch, we use this path.

3fill in blank

hard

Fix the error in the pipeline script to load the correct Jenkinsfile per branch.

Jenkins

pipeline {
  agent any
  stages {
    stage('Checkout') {
      steps {
        checkout scm
      }
    }
    stage('Build') {
      steps {
        load '[1]'
      }
    }
  }
}

Drag options to blanks, or click blank then click option'

AJenkinsfile-${env.BRANCH_NAME}

BJenkinsfile.${env.BRANCH_NAME}

CJenkinsfile

DJenkinsfile_${env.BRANCH_NAME}

Attempts:

3 left

💡 Hint

Common Mistakes

Using dot notation inside string interpolation incorrectly.

Using underscores or dots instead of dash.

The Jenkinsfile path should be constructed with a dash before the branch name, like Jenkinsfile-feature.

4fill in blank

hard

Fill both blanks to define a pipeline that loads a Jenkinsfile based on the branch name and runs it.

Jenkins

def file = 'Jenkinsfile[1][2]'
load file

Drag options to blanks, or click blank then click option'

A-

B_

Cenv.BRANCH_NAME

DBRANCH_NAME

Attempts:

3 left

💡 Hint

Common Mistakes

Using underscore instead of dash.

Using undefined variable names.

The Jenkinsfile name is constructed by joining 'Jenkinsfile', a dash, and the branch name from env.BRANCH_NAME.

5fill in blank

hard

Fill all three blanks to create a Jenkins pipeline that checks out the current branch, selects the Jenkinsfile path, and loads it.

Jenkins

pipeline {
  agent any
  stages {
    stage('Checkout') {
      steps {
        checkout([$class: 'GitSCM', branches: [[name: '[1]']], userRemoteConfigs: [[url: 'https://github.com/example/repo.git']]])
      }
    }
    stage('Load Jenkinsfile') {
      steps {
        def file = '[2][3]'
        load file
      }
    }
  }
}

Drag options to blanks, or click blank then click option'

Aenv.BRANCH_NAME

BJenkinsfile-

CJenkinsfile

Denv.BRANCH

Attempts:

3 left

💡 Hint

Common Mistakes

Using incorrect environment variable names.

Not matching branch name in checkout and Jenkinsfile path.

The pipeline checks out the current branch using env.BRANCH_NAME, then constructs the Jenkinsfile path by joining 'Jenkinsfile-' and the branch name from env.BRANCH_NAME.

Practice

1. What is the main benefit of having a separate Jenkinsfile in each branch?

easy

A. It allows customizing the pipeline for each branch independently.

B. It forces all branches to use the same pipeline configuration.

C. It disables pipeline execution on branches without a Jenkinsfile.

D. It merges all branch pipelines into one global pipeline.

Solution

1. Step 1: Understand Jenkinsfile per branch concept

   Each branch can have its own Jenkinsfile, allowing different pipeline steps or settings per branch.

2. Step 2: Compare options

   It allows customizing the pipeline for each branch independently. correctly states the benefit. Options A, B, and D describe incorrect behaviors.

3. Final Answer:

   It allows customizing the pipeline for each branch independently. -> Option A

4. Quick Check:

   Separate Jenkinsfiles = branch-specific pipelines [OK]

Hint: Separate Jenkinsfiles mean separate pipelines per branch [OK]

Common Mistakes:

• Thinking one Jenkinsfile applies to all branches
• Assuming Jenkinsfile absence disables pipeline
• Believing pipelines merge automatically

2. Which of the following is the correct syntax to checkout from a specific branch in a multibranch pipeline?

easy

A. pipeline { agent any; stages { stage('Build') { steps { checkout([$class: 'GitSCM', branches: ['refs/heads/feature'], userRemoteConfigs: [[url: 'https://repo.git']]]) } } } }

B. pipeline { agent any; stages { stage('Build') { steps { git branch: 'main', url: 'https://repo.git' } } } }

C. pipeline { agent any; stages { stage('Build') { steps { load 'Jenkinsfile' } } } }

D. pipeline { agent any; stages { stage('Build') { steps { script { checkout scm } } } } }

Solution

1. Step 1: Identify correct syntax for branch checkout

   Using the git step with branch and url is the simplest correct way to checkout a specific branch.

2. Step 2: Analyze options

   The snippet using git branch: 'main', url: 'https://repo.git' is correct. The snippet using checkout([$class: 'GitSCM', branches: ['refs/heads/feature'], userRemoteConfigs: [[url: 'https://repo.git']]]) has invalid syntax for branches (expects list of maps like [[name: 'refs/heads/feature']]). The snippet using script { checkout scm } checks out the current SCM without specifying a branch. The snippet using load 'Jenkinsfile' loads a Groovy script but does not checkout a branch.

3. Final Answer:

   pipeline { agent any; stages { stage('Build') { steps { git branch: 'main', url: 'https://repo.git' } } } } -> Option B

4. Quick Check:

   Use git step with branch and url [OK]

Hint: Use git step with branch and url to specify branch [OK]

Common Mistakes:

• Using load to get Jenkinsfile instead of checkout
• Not specifying branch in checkout
• Confusing checkout scm with git step

3. Given this Jenkinsfile snippet inside a branch:

pipeline {
  agent any
  stages {
    stage('Test') {
      steps {
        script {
          if (env.BRANCH_NAME == 'main') {
            echo 'Deploying main branch'
          } else {
            echo 'Deploying feature branch'
          }
        }
      }
    }
  }
}

What will Jenkins print if the branch is named feature/login?

medium

A. No output

B. Deploying main branch

C. Deploying feature branch

D. Pipeline fails with error

Solution

1. Step 1: Understand branch name condition

   The script checks if env.BRANCH_NAME equals 'main'. If yes, it prints 'Deploying main branch', else 'Deploying feature branch'.

2. Step 2: Apply branch name 'feature/login'

   Since the branch is 'feature/login', it does not equal 'main', so the else branch runs printing 'Deploying feature branch'.

3. Final Answer:

   Deploying feature branch -> Option C

4. Quick Check:

   Branch name check leads to else output [OK]

Hint: Check branch name string exactly for condition [OK]

Common Mistakes:

• Assuming partial match triggers main branch output
• Confusing env.BRANCH_NAME with other variables
• Expecting no output if branch is not main

4. You have a Jenkinsfile in your feature branch but the pipeline fails with error: groovy.lang.MissingPropertyException: No such property: env for class. What is the likely cause?

medium

A. The env variable is used outside a script block.

B. The Jenkinsfile is missing the pipeline block.

C. The branch name is incorrect in the Jenkinsfile.

D. The Jenkinsfile is not committed to the branch.

Solution

1. Step 1: Understand env variable usage

   In declarative pipelines, env variables must be accessed inside a script block to use Groovy expressions.

2. Step 2: Analyze error cause

   The error indicates env is not recognized, likely because it is used outside a script block where Groovy code runs.

3. Final Answer:

   The env variable is used outside a script block. -> Option A

4. Quick Check:

   Use env only inside script blocks [OK]

Hint: Access env variables only inside script blocks [OK]

Common Mistakes:

• Using env directly in steps without script
• Assuming missing pipeline block causes env error
• Not committing Jenkinsfile to branch

5. You want to maintain a single Jenkinsfile in the main branch but customize pipeline steps for feature/* branches without creating Jenkinsfiles in each feature branch. Which approach is best?

hard

A. Configure Jenkins to ignore feature branches.

B. Create symbolic links to the main Jenkinsfile in each feature branch.

C. Use separate Jenkinsfiles in each feature branch and merge them manually.

D. Use when { branch 'feature/*' } conditions inside the Jenkinsfile to run different stages.

Solution

1. Step 1: Understand single Jenkinsfile with branch conditions

   You can use when { branch 'pattern' } in declarative pipelines to run stages only on matching branches.

2. Step 2: Evaluate options

   Use when { branch 'feature/*' } conditions inside the Jenkinsfile to run different stages. uses branch conditions inside one Jenkinsfile, which fits the requirement. Create symbolic links to the main Jenkinsfile in each feature branch. is not practical or supported. Use separate Jenkinsfiles in each feature branch and merge them manually. contradicts the goal of single Jenkinsfile. Configure Jenkins to ignore feature branches. ignores feature branches, not customizing them.

3. Final Answer:

   Use when { branch 'feature/*' } conditions inside the Jenkinsfile to run different stages. -> Option D

4. Quick Check:

   Branch conditions enable single Jenkinsfile customization [OK]

Hint: Use when branch conditions for per-branch steps [OK]

Common Mistakes:

• Trying to link Jenkinsfiles across branches
• Creating multiple Jenkinsfiles despite single file goal
• Ignoring feature branches instead of customizing