How to Sort Object by Key in JavaScript: Simple Guide
To sort an object by its keys in JavaScript, first get the keys using
Object.keys(), then sort them with Array.prototype.sort(), and finally create a new object with keys in sorted order. This approach keeps the original object unchanged and returns a new sorted object.Syntax
Use Object.keys(obj) to get all keys, then sort them with keys.sort(). Create a new object by iterating over sorted keys and assigning values from the original object.
This process does not change the original object but returns a new one with keys in sorted order.
javascript
const sortedObj = Object.keys(obj) .sort() .reduce((acc, key) => { acc[key] = obj[key]; return acc; }, {});
Example
This example shows how to sort an object by its keys alphabetically and create a new sorted object.
javascript
const obj = { banana: 2, apple: 5, cherry: 3 }; const sortedObj = Object.keys(obj) .sort() .reduce((acc, key) => { acc[key] = obj[key]; return acc; }, {}); console.log(sortedObj);
Output
{"apple":5,"banana":2,"cherry":3}
Common Pitfalls
One common mistake is trying to sort the object directly, but JavaScript objects do not maintain order reliably. Sorting keys and creating a new object is necessary.
Another pitfall is modifying the original object, which is not recommended if you want to keep data safe.
javascript
const obj = { b: 1, a: 2 }; // Wrong: sorting keys but not creating new object obj.sort(); // Error: obj.sort is not a function // Right: create new sorted object const sortedObj = Object.keys(obj) .sort() .reduce((acc, key) => { acc[key] = obj[key]; return acc; }, {}); console.log(sortedObj);
Output
{"a":2,"b":1}
Quick Reference
- Object.keys(obj): Get all keys from the object.
- keys.sort(): Sort keys alphabetically.
- Array.reduce(): Build a new object with sorted keys.
- Original object remains unchanged.
Key Takeaways
Use Object.keys() and sort() to get sorted keys of an object.
Create a new object with sorted keys to maintain order.
Do not try to sort the object directly; objects do not guarantee key order.
Keep the original object unchanged for safer code.
Use reduce() to build the sorted object cleanly and simply.