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Javaprogramming~10 mins

Why exception handling is required in Java - Test Your Understanding

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Test this pattern10 questions across easy, medium, and hard to know if this pattern is strong
Practice - 5 Tasks
Answer the questions below
1fill in blank
easy

Complete the code to catch an exception when dividing by zero.

Java
try {
    int result = 10 / [1];
} catch (ArithmeticException e) {
    System.out.println("Cannot divide by zero.");
}
Drag options to blanks, or click blank then click option'
A10
B1
C2
D0
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Using a non-zero number which does not cause an exception.
2fill in blank
medium

Complete the code to handle a possible null pointer exception.

Java
String text = null;
try {
    int length = text.[1]();
} catch (NullPointerException e) {
    System.out.println("Text is null.");
}
Drag options to blanks, or click blank then click option'
Alength()
BcharAt
Clength
DtoString
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Using length without parentheses which is invalid for String.
3fill in blank
hard

Fix the error in the code to properly catch exceptions.

Java
try {
    int[] arr = new int[3];
    int value = arr[5];
} catch ([1] e) {
    System.out.println("Index out of bounds.");
}
Drag options to blanks, or click blank then click option'
AArithmeticException
BNullPointerException
CArrayIndexOutOfBoundsException
DIOException
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Catching the wrong exception type that does not match the error.
4fill in blank
hard

Fill both blanks to create a try-catch block that handles file reading exceptions.

Java
try {
    FileReader file = new FileReader("test.txt");
    BufferedReader reader = new BufferedReader(file);
    String line = reader.readLine();
} catch ([1] e) {
    System.out.println("File not found.");
} catch ([2] e) {
    System.out.println("IO error occurred.");
}
Drag options to blanks, or click blank then click option'
AFileNotFoundException
BNullPointerException
CIOException
DArithmeticException
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Swapping the order of exceptions or using unrelated exceptions.
5fill in blank
hard

Fill all three blanks to create a method that throws and catches a custom exception.

Java
class MyException extends Exception {}

public class Test {
    public static void check(int num) throws [1] {
        if (num < 0) {
            throw new [2]();
        }
    }

    public static void main(String[] args) {
        try {
            check(-1);
        } catch ([3] e) {
            System.out.println("Custom exception caught.");
        }
    }
}
Drag options to blanks, or click blank then click option'
AMyException
DException
Attempts:
3 left
πŸ’‘ Hint
Common Mistakes
Using Exception instead of the custom exception class.

Practice

(1/5)
1. Why is exception handling required in Java programs?
easy
A. To prevent the program from crashing when an error occurs
B. To make the program run faster
C. To increase the size of the program
D. To avoid writing any code

Solution

  1. Step 1: Understand what happens without exception handling

    Without exception handling, errors cause the program to stop abruptly, leading to crashes.
  2. Step 2: Role of exception handling

    Exception handling catches errors and allows the program to continue or handle the error gracefully.
  3. Final Answer:

    To prevent the program from crashing when an error occurs -> Option A
  4. Quick Check:

    Exception handling prevents crashes [OK]
Hint: Exception handling stops crashes by managing errors [OK]
Common Mistakes:
  • Thinking exception handling makes code faster
  • Believing it increases program size unnecessarily
  • Assuming it removes the need to write code
2. Which of the following is the correct syntax to start exception handling in Java?
easy
A. try(Exception e) { /* code */ } catch { /* handle */ }
B. catch { /* code */ } try(Exception e) { /* handle */ }
C. handle { /* code */ } try(Exception e) { /* handle */ }
D. try { /* code */ } catch(Exception e) { /* handle */ }

Solution

  1. Step 1: Identify the correct order of try-catch blocks

    In Java, the try block comes first, followed by one or more catch blocks.
  2. Step 2: Check syntax correctness

    try { /* code */ } catch(Exception e) { /* handle */ } correctly uses try { } followed by catch(Exception e) { } which is valid syntax.
  3. Final Answer:

    try { /* code */ } catch(Exception e) { /* handle */ } -> Option D
  4. Quick Check:

    try block first, then catch [OK]
Hint: Try block comes before catch block in Java syntax [OK]
Common Mistakes:
  • Swapping try and catch keywords
  • Using 'handle' instead of 'catch'
  • Placing exception parameter incorrectly
3. What will be the output of the following Java code?
public class Test {
  public static void main(String[] args) {
    try {
      int result = 10 / 0;
      System.out.println(result);
    } catch (ArithmeticException e) {
      System.out.println("Error caught: " + e.getMessage());
    }
  }
}
medium
A. Error caught: / by zero
B. 10
C. 0
D. Program crashes with ArithmeticException

Solution

  1. Step 1: Identify the error in the try block

    The code attempts to divide 10 by 0, which causes an ArithmeticException.
  2. Step 2: Check how the exception is handled

    The catch block catches ArithmeticException and prints "Error caught: " plus the exception message "/ by zero".
  3. Final Answer:

    Error caught: / by zero -> Option A
  4. Quick Check:

    Division by zero caught and message printed [OK]
Hint: Division by zero triggers ArithmeticException caught by catch [OK]
Common Mistakes:
  • Expecting program to print 10 or 0
  • Thinking program crashes without catch
  • Ignoring exception message in output
4. Identify the error in the following Java code snippet related to exception handling:
try {
  int[] arr = new int[3];
  System.out.println(arr[5]);
} catch (Exception e) {
  System.out.println("Exception caught");
}
medium
A. ArrayIndexOutOfBoundsException is not caught because catch is for Exception
B. The code will compile but throw an uncaught exception
C. No error; the exception will be caught and message printed
D. Syntax error in try-catch block

Solution

  1. Step 1: Understand the exception thrown

    Accessing arr[5] causes ArrayIndexOutOfBoundsException, which is a subclass of Exception.
  2. Step 2: Check catch block type

    The catch block catches Exception, so it will catch ArrayIndexOutOfBoundsException and print the message.
  3. Final Answer:

    No error; the exception will be caught and message printed -> Option C
  4. Quick Check:

    Exception catch block catches all exceptions [OK]
Hint: Catch Exception catches all exceptions including subclasses [OK]
Common Mistakes:
  • Thinking ArrayIndexOutOfBoundsException is not caught by Exception
  • Assuming code crashes without catch
  • Believing syntax error exists in try-catch
5. You want to read a file in Java but ensure the program continues even if the file is missing. Which approach best uses exception handling to achieve this?
hard
A. Use if-else to check file existence without try-catch
B. Use try block to read file and catch FileNotFoundException to handle missing file
C. Use only catch block without try block
D. Ignore exceptions and let the program crash if file is missing

Solution

  1. Step 1: Understand the problem of missing file

    Reading a missing file throws FileNotFoundException, which must be handled to avoid crash.
  2. Step 2: Use try-catch to handle exception

    Placing file reading code inside try and catching FileNotFoundException allows graceful handling and program continuation.
  3. Final Answer:

    Use try block to read file and catch FileNotFoundException to handle missing file -> Option B
  4. Quick Check:

    Try-catch handles file errors to keep program running [OK]
Hint: Try reading file, catch FileNotFoundException to avoid crash [OK]
Common Mistakes:
  • Ignoring exceptions causing program crash
  • Using catch without try block
  • Relying only on if-else without exception handling