[Solved] Identify the problem in this Java code:try { int[] nums = new int[3]; nums[3] = 10;} catch (NullPointerException e) { System.out.println("Null pointer");} | Java

Java - Exception Handling

Identify the problem in this Java code:

try {
  int[] nums = new int[3];
  nums[3] = 10;
} catch (NullPointerException e) {
  System.out.println("Null pointer");
}

ACatch block does not handle ArrayIndexOutOfBoundsException

BArray size is incorrect

CTry block syntax is wrong

DNo exception will occur

Step-by-Step Solution

Solution:

Step 1: Analyze the exception thrown
Accessing nums[3] causes ArrayIndexOutOfBoundsException, not NullPointerException.
Step 2: Check catch block exception type
Catch block only handles NullPointerException, so the actual exception is not caught.
Final Answer:
Catch block does not handle ArrayIndexOutOfBoundsException -> Option A
Quick Check:
Catch type mismatch = uncaught exception [OK]

Quick Trick: Catch block must match thrown exception type [OK]

Common Mistakes:

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