[Solved] Find the error in this Java code snippet:try { int x = 5 / 0;} catch (Exception e) { System.out.println("Error");} | Java

Java - Exception Handling

Find the error in this Java code snippet:

try {
  int x = 5 / 0;
} catch (Exception e) {
  System.out.println("Error");
}

ACatch block should catch ArithmeticException

BDivision by zero causes compile-time error

CMissing finally block causes error

DNo error, code is correct

Step-by-Step Solution

Solution:

Step 1: Check for compile-time errors
Division by zero in Java is a runtime error, so no compile-time error occurs.
Step 2: Verify catch block correctness
Catch block catches Exception, which includes ArithmeticException, so it is valid.
Final Answer:
No error, code is correct -> Option D
Quick Check:
Catch Exception covers all exceptions [OK]

Quick Trick: Catch Exception handles all exceptions including arithmetic [OK]

Common Mistakes:

Master "Exception Handling" in Java

9 interactive learning modes - each teaches the same concept differently

More Java Quizzes

Find the error in this Java code snippet: