[Solved] What will be the output of the following Java code?public class Example { public static void main(String[] args) { try { int value = 100 / 0; System.out.println(value);... | Java

Java - Exception Handling

What will be the output of the following Java code?

public class Example {
  public static void main(String[] args) {
    try {
      int value = 100 / 0;
      System.out.println(value);
    } catch (ArithmeticException e) {
      System.out.println("Division by zero error");
    }
  }
}

ACompilation error

B100

C0

DDivision by zero error

Step-by-Step Solution

Solution:

Step 1: Analyze the try block
The code attempts to divide 100 by 0, which causes an ArithmeticException.
Step 2: Catch block execution
The catch block catches the ArithmeticException and prints "Division by zero error".
Final Answer:
Division by zero error -> Option D
Quick Check:
Division by zero triggers ArithmeticException [OK]

Quick Trick: Division by zero triggers ArithmeticException catch [OK]

Common Mistakes:

Expecting the program to print 100
Assuming division by zero returns 0
Thinking this causes a compile-time error

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What will be the output of the following Java code?

Step 1: Analyze the try block

Step 2: Catch block execution

Final Answer:

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