Throws keyword in Java - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare that the method may throw an exception.

Java

public void readFile() [1] IOException { }

Drag options to blanks, or click blank then click option'

Athrow

Bthrows

CthrowsException

DthrowsError

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'throw' instead of 'throws' in method declaration

Misspelling the keyword

Placing the keyword inside the method body

The throws keyword declares that a method might throw an exception.

2fill in blank

medium

Complete the method declaration to indicate it throws multiple exceptions.

Java

public void process() [1] IOException, SQLException { }

Drag options to blanks, or click blank then click option'

Athrow

BthrowsException

Cthrows

DthrowsError

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'throw' instead of 'throws'

Separating exceptions with semicolons instead of commas

Omitting the keyword entirely

The throws keyword can list multiple exceptions separated by commas.

3fill in blank

hard

Fix the error in the method declaration that incorrectly uses the throws keyword.

Java

public void save() [1] IOException { }

Drag options to blanks, or click blank then click option'

Athrows

BthrowsError

CthrowsException

Dthrow

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'throw' instead of 'throws'

Misspelling the keyword

Placing the keyword inside the method body

The correct keyword to declare exceptions is throws, not throw.

4fill in blank

hard

Complete the code to declare a method that throws two exceptions.

Java

public void connect() [1] IOException, SQLException { }

Drag options to blanks, or click blank then click option'

Athrows

B,

C;

Dthrow

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'throw' instead of 'throws'

Separating exceptions with semicolons

Repeating the keyword before each exception

Use throws once, then separate exceptions with a comma.

5fill in blank

hard

Complete the code to declare a method throwing three exceptions correctly.

Java

public void execute() [1] IOException, SQLException, NullPointerException { }

Drag options to blanks, or click blank then click option'

Athrows

B,

C;

Dthrow

Attempts:

3 left

💡 Hint

Common Mistakes

Using multiple 'throws' keywords

Separating exceptions with semicolons

Using 'throw' instead of 'throws'

Use throws once, then separate all exceptions with commas.

Practice

1.

What is the main purpose of the throws keyword in Java?

easy

A. To declare that a method might throw certain checked exceptions

B. To catch exceptions inside a method

C. To create a new exception object

D. To stop the program immediately when an error occurs

Solution

1. Step 1: Understand the role of throws

   The throws keyword is used in a method signature to declare that the method might throw certain checked exceptions.

2. Step 2: Differentiate from other keywords

   It does not catch exceptions (that's try-catch), nor create exceptions or stop the program immediately.

3. Final Answer:

   To declare that a method might throw certain checked exceptions -> Option A

4. Quick Check:

   throws declares exceptions [OK]

Hint: Remember: throws declares, catch handles exceptions [OK]

Common Mistakes:

• Confusing throws with catch
• Thinking throws creates exceptions
• Believing throws stops program immediately

2.

Which of the following is the correct way to declare a method that might throw an IOException?

public void readFile() _____ IOException { }

easy

A. thrown

B. throw

C. throws

D. throws new

Solution

1. Step 1: Recall correct syntax for exception declaration

   In Java, the keyword to declare exceptions a method might throw is throws.

2. Step 2: Check options for syntax correctness

   throw is used to actually throw an exception inside method body, not in declaration. thrown and throws new are invalid.

3. Final Answer:

   throws -> Option C

4. Quick Check:

   Method declaration uses throws [OK]

Hint: Method declarations use 'throws', not 'throw' [OK]

Common Mistakes:

• Using 'throw' instead of 'throws' in method signature
• Adding 'new' after throws
• Using non-existent keywords like 'thrown'

3.

What will be the output of the following code?

import java.io.*;

public class Test {
    public static void risky() throws IOException {
        throw new IOException("Error happened");
    }
    public static void main(String[] args) {
        try {
            risky();
        } catch (IOException e) {
            System.out.println(e.getMessage());
        }
    }
}

medium

A. Error happened

B. Compilation error due to missing throws

C. No output

D. Runtime error without message

Solution

1. Step 1: Analyze method throwing exception

   The method risky() declares it throws IOException and actually throws it with message "Error happened".

2. Step 2: Check exception handling in main

   The main method calls risky() inside a try block and catches IOException, printing the exception message.

3. Final Answer:

   Error happened -> Option A

4. Quick Check:

   Exception caught and message printed [OK]

Hint: Thrown exceptions must be caught or declared [OK]

Common Mistakes:

• Thinking throws causes compile error if caught
• Expecting no output because exception thrown
• Confusing throws with throw inside method body

4.

Identify the error in the following code snippet:

public void process() {
    riskyMethod() throws IOException;
}

medium

A. Incorrect use of throws keyword inside method body

B. Missing try-catch block around riskyMethod() call

C. Method process() should declare throws IOException

D. All of the above

Solution

1. Step 1: Check syntax of throws usage

   The throws keyword cannot be used inside a method body; it belongs in the method signature.

2. Step 2: Analyze exception handling requirements

   Calling riskyMethod() which throws IOException requires either a try-catch block or declaring throws IOException in process().

3. Step 3: Combine all errors

   All these issues are present: wrong throws usage, missing try-catch, and missing throws declaration.

4. Final Answer:

   All of the above -> Option D

5. Quick Check:

   Throws only in signature + handle exceptions [OK]

Hint: Throws keyword only in method signature, not inside body [OK]

Common Mistakes:

• Using throws inside method body
• Not handling checked exceptions properly
• Forgetting to declare throws in method signature

5.

You have a method readData() that calls two other methods: openFile() and parseFile(). Both can throw IOException. How should you declare readData() to properly handle exceptions?

hard

A. Do nothing, exceptions will be handled automatically

B. Declare readData() with throws IOException and let caller handle it

C. Declare readData() with throws Exception to cover all exceptions

D. Use try-catch inside readData() to catch and ignore exceptions

Solution

1. Step 1: Understand exception propagation

   If openFile() and parseFile() throw IOException, readData() must either handle or declare these exceptions.

2. Step 2: Choose proper declaration

   Declaring throws IOException in readData() lets the caller decide how to handle exceptions, keeping code clean and clear.

3. Step 3: Evaluate other options

   Ignoring exceptions is bad practice. Declaring throws Exception is too broad. Exceptions are not handled automatically.

4. Final Answer:

   Declare readData() with throws IOException and let caller handle it -> Option B

5. Quick Check:

   Declare checked exceptions to propagate [OK]

Hint: Declare throws for checked exceptions to pass responsibility [OK]

Common Mistakes:

• Ignoring exceptions instead of declaring or catching
• Declaring too broad exceptions like Exception
• Assuming exceptions are handled automatically