Given the interface Utils with a static method isEven(int n) that returns true if n is even, how can you use this method inside a class NumberChecker to filter even numbers from a list List<Integer> nums using streams?

hard📝 Application Q15 of 15

Java - Interfaces

Given the interface Utils with a static method isEven(int n) that returns true if n is even, how can you use this method inside a class NumberChecker to filter even numbers from a list List<Integer> nums using streams?

Anums.stream().filter(Utils::isEven).toList();

Bnums.stream().filter(n -> Utils.isEven()).toList();

Cnums.stream().filter(n -> isEven(n)).toList();

Dnums.stream().filter(n -> Utils.isEven(n)).collect();

Step-by-Step Solution

Solution:

Step 1: Understand method reference syntax
Static methods can be referenced as InterfaceName::methodName in streams.
Step 2: Analyze options for correct syntax
nums.stream().filter(Utils::isEven).toList(); uses method reference correctly. The lambda n -> Utils.isEven() misses argument n, n -> isEven(n) lacks interface qualification, and .collect() requires a collector.
Final Answer:
nums.stream().filter(Utils::isEven).toList(); -> Option A
Quick Check:
Use InterfaceName::staticMethod for stream filters [OK]

Quick Trick: Use InterfaceName::methodName for static method references in streams [OK]

Common Mistakes:

Calling static method without argument in lambda
Using instance method syntax for static methods
Wrong terminal operation like collect() without collector

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More Java Quizzes

Given the interface Utils with a static method isEven(int n) that returns true if n is even, how can you use this method inside a class NumberChecker to filter even numbers from a list List<Integer> nums using streams?

Step 1: Understand method reference syntax

Step 2: Analyze options for correct syntax

Final Answer:

Quick Check:

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