[Solved] What will be the output of this code?class MyException extends Exception {} public class Test { public static void main(String[] args) { try { throw new MyException();... | Java

Java - Custom Exceptions

What will be the output of this code?

class MyException extends Exception {}

public class Test {
  public static void main(String[] args) {
    try {
      throw new MyException();
    } catch (MyException e) {
      System.out.println("Caught MyException");
    } catch (Exception e) {
      System.out.println("Caught Exception");
    }
  }
}

ACaught Exception

BNo output

CCaught MyException

DCompilation error

Step-by-Step Solution

Solution:

Step 1: Analyze the thrown exception type
The code throws MyException, a subclass of Exception.
Step 2: Check catch block order
The first catch matches MyException exactly, so it executes and prints the message.
Final Answer:
Caught MyException -> Option C
Quick Check:
Specific catch runs before general one [OK]

Quick Trick: Catch specific exceptions before general ones [OK]

Common Mistakes:

Expecting the general Exception catch to run first
Thinking code won't compile due to catch order
Assuming no output because exception is thrown

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More Java Quizzes

What will be the output of this code?

Step 1: Analyze the thrown exception type

Step 2: Check catch block order

Final Answer:

Quick Check:

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