Runtime polymorphism in Java - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare a method that can be overridden.

Java

public class Animal {
    public void [1]() {
        System.out.println("Animal sound");
    }
}

Drag options to blanks, or click blank then click option'

AmakeSound

Bspeak

Csound

Dnoise

Attempts:

3 left

💡 Hint

Common Mistakes

Using a method name that is not descriptive or inconsistent with subclass methods.

The method name makeSound is used to demonstrate runtime polymorphism by overriding it in subclasses.

2fill in blank

medium

Complete the code to override the method in the subclass.

Java

public class Dog extends Animal {
    @Override
    public void [1]() {
        System.out.println("Bark");
    }
}

Drag options to blanks, or click blank then click option'

AmakeSound

Bnoise

Cspeak

Dsound

Attempts:

3 left

💡 Hint

Common Mistakes

Using a different method name that does not override the superclass method.

The subclass Dog overrides the makeSound method to provide its own implementation.

3fill in blank

hard

Fix the error in the code to call the overridden method at runtime.

Java

Animal myAnimal = new Dog();
myAnimal.[1]();

Drag options to blanks, or click blank then click option'

Asound

BmakeSound

Cspeak

Dnoise

Attempts:

3 left

💡 Hint

Common Mistakes

Calling a method name that does not exist in the superclass reference.

Calling makeSound() on the Animal reference invokes the overridden method in Dog at runtime.

4fill in blank

hard

Fill both blanks to complete the code that demonstrates runtime polymorphism with two subclasses.

Java

Animal myAnimal1 = new Dog();
Animal myAnimal2 = new Cat();
myAnimal1.[1]();
myAnimal2.[2]();

Drag options to blanks, or click blank then click option'

AmakeSound

Bsound

Cspeak

Dnoise

Attempts:

3 left

💡 Hint

Common Mistakes

Using different method names for each call that do not exist in the superclass.

Both Dog and Cat override the makeSound() method, so calling it on Animal references demonstrates runtime polymorphism.

5fill in blank

hard

Fill all three blanks to complete the code that uses runtime polymorphism with method overriding and dynamic method dispatch.

Java

class Animal {
    public void [1]() {
        System.out.println("Animal sound");
    }
}

class Dog extends Animal {
    @Override
    public void [2]() {
        System.out.println("Bark");
    }
}

public class Test {
    public static void main(String[] args) {
        Animal myAnimal = new Dog();
        myAnimal.[3]();
    }
}

Drag options to blanks, or click blank then click option'

AmakeSound

Bsound

Cspeak

Dnoise

Attempts:

3 left

💡 Hint

Common Mistakes

Using different method names in declaration, override, or call causing compile errors.

The method makeSound() is declared in Animal, overridden in Dog, and called on an Animal reference holding a Dog object to demonstrate runtime polymorphism.

Practice

1. What is runtime polymorphism in Java?

easy

A. Creating multiple objects of the same class

B. Using multiple classes with the same name

C. Choosing which method to call during program execution based on object type

D. Writing methods with different names in the same class

Solution

1. Step 1: Understand polymorphism concept

   Polymorphism means many forms; in Java, it allows methods to behave differently based on object type.

2. Step 2: Identify runtime polymorphism

   Runtime polymorphism happens when the program decides which overridden method to call during execution, not before.

3. Final Answer:

   Choosing which method to call during program execution based on object type -> Option C

4. Quick Check:

   Runtime polymorphism = method choice at runtime [OK]

Hint: Runtime polymorphism means method choice happens while running [OK]

Common Mistakes:

• Confusing compile-time and runtime polymorphism
• Thinking it means multiple classes with same name
• Believing it is about method overloading

2. Which syntax correctly shows method overriding for runtime polymorphism in Java?

easy

A. class Parent { void show() {} } class Child extends Parent { void show() {} }

B. class Parent { void show() {} } class Child extends Parent { void display() {} }

C. class Parent { void show() {} } class Child { void show() {} }

D. class Parent { void show() {} } class Child extends Parent { void show(int x) {} }

Solution

1. Step 1: Check method overriding rules

   Method overriding requires same method name and parameters in subclass extending superclass.

2. Step 2: Match options with overriding

   class Parent { void show() {} } class Child extends Parent { void show() {} } shows subclass overriding show() method correctly; others differ in method name or parameters.

3. Final Answer:

   class Parent { void show() {} } class Child extends Parent { void show() {} } -> Option A

4. Quick Check:

   Same method name and parameters in subclass = overriding [OK]

Hint: Overriding needs same method name and parameters in subclass [OK]

Common Mistakes:

• Changing method name in subclass instead of overriding
• Changing method parameters (overloading, not overriding)
• Not extending the parent class

3. What is the output of this code?

class Animal {
  void sound() { System.out.println("Animal sound"); }
}
class Dog extends Animal {
  void sound() { System.out.println("Bark"); }
}
public class Test {
  public static void main(String[] args) {
    Animal a = new Dog();
    a.sound();
  }
}

medium

A. Bark

B. Animal sound

C. Compilation error

D. Runtime error

Solution

1. Step 1: Understand object and reference types

   Reference is of type Animal, but object is Dog, so overridden method in Dog is called.

2. Step 2: Identify method called at runtime

   Due to runtime polymorphism, sound() of Dog runs, printing "Bark".

3. Final Answer:

   Bark -> Option A

4. Quick Check:

   Overridden method runs based on object type [OK]

Hint: Method called depends on object type, not reference type [OK]

Common Mistakes:

• Thinking reference type decides method called
• Expecting superclass method output
• Confusing compile-time and runtime behavior

4. Find the error in this code related to runtime polymorphism:

class Parent {
  void show() { System.out.println("Parent"); }
}
class Child extends Parent {
  void show(int x) { System.out.println("Child " + x); }
}
public class Test {
  public static void main(String[] args) {
    Parent p = new Child();
    p.show();
  }
}

medium

A. Parent class method show() is private

B. Child class does not override show() method correctly

C. Cannot assign Child object to Parent reference

D. Missing main method

Solution

1. Step 1: Check method overriding in Child class

   Child defines show(int x), which is overloading, not overriding show().

2. Step 2: Understand method call on Parent reference

   Parent reference calls show() with no arguments, but Child has no overriding method, so Parent's method runs.

3. Final Answer:

   Child class does not override show() method correctly -> Option B

4. Quick Check:

   Overriding needs exact method signature match [OK]

Hint: Overriding needs same method signature, not just same name [OK]

Common Mistakes:

• Thinking overloading is overriding
• Expecting Child's show(int) to override show()
• Ignoring method parameters in overriding

5. Given these classes:

class Vehicle {
  void start() { System.out.println("Vehicle starts"); }
}
class Car extends Vehicle {
  void start() { System.out.println("Car starts"); }
}
class Bike extends Vehicle {
  void start() { System.out.println("Bike starts"); }
}
public class Test {
  public static void main(String[] args) {
    Vehicle[] vehicles = {new Car(), new Bike(), new Vehicle()};
    for (Vehicle v : vehicles) {
      v.start();
    }
  }
}

What is the output when this program runs?

hard

A. Vehicle starts
Vehicle starts
Vehicle starts

B. Compilation error due to array initialization

C. Car starts
Vehicle starts
Bike starts

D. Car starts
Bike starts
Vehicle starts

Solution

1. Step 1: Analyze array elements and their types

   Array holds objects: Car, Bike, Vehicle, all as Vehicle references.

2. Step 2: Understand method calls in loop

   Each start() call runs overridden method of actual object type due to runtime polymorphism.

3. Step 3: Determine output lines

   Car prints "Car starts", Bike prints "Bike starts", Vehicle prints "Vehicle starts" in order.

4. Final Answer:

   Car starts Bike starts Vehicle starts -> Option D

5. Quick Check:

   Overridden methods run per object type in array [OK]

Hint: Loop calls overridden methods based on actual object type [OK]

Common Mistakes:

• Expecting all calls to run Vehicle's method
• Confusing array reference type with object type
• Thinking array initialization causes error