Finally block in Java - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to ensure the block always runs after try.

Java

try {
    System.out.println("Try block");
} [1] {
    System.out.println("This always runs");
}

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Afinally

Bfinal

Ccatch

Dcatch(Exception e)

Attempts:

3 left

💡 Hint

Common Mistakes

Using catch without specifying exception

Using final instead of finally

The finally block always runs after the try block, regardless of exceptions.

2fill in blank

medium

Complete the code to catch an exception and still run the final block.

Java

try {
    int a = 5 / 0;
} [1] (ArithmeticException e) {
    System.out.println("Caught division by zero");
} finally {
    System.out.println("Always runs");
}

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AcatchError

Bcatch

Ccatch(Exception e)

Dfinal

Attempts:

3 left

💡 Hint

Common Mistakes

Using final instead of finally

Writing catch without parentheses

The catch block handles exceptions. It must be followed by parentheses with the exception type.

3fill in blank

hard

Fix the error in the finally block declaration.

Java

try {
    System.out.println("Try block");
} catch(Exception e) {
    System.out.println("Exception caught");
} [1] {
    System.out.println("This always runs");
}

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Afinal

Bfinalize

Ccatch

Dfinally

Attempts:

3 left

💡 Hint

Common Mistakes

Using final instead of finally

Using catch instead of finally

The correct keyword for the block that always runs is finally.

4fill in blank

hard

Fill both blanks to complete the try-catch-finally structure.

Java

try {
    int[] arr = new int[2];
    System.out.println(arr[[1]]);
} [2] (ArrayIndexOutOfBoundsException e) {
    System.out.println("Index error caught");
} finally {
    System.out.println("Cleanup done");
}

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A3

Bcatch

C2

Dfinal

Attempts:

3 left

💡 Hint

Common Mistakes

Using index 2 which is also out of bounds but less clear

Using final instead of catch

The index 3 is out of bounds for an array of size 2, causing an exception caught by the catch block.

5fill in blank

hard

Fill all three blanks to create a try-catch-finally that handles null pointer exception.

Java

String s = null;
try {
    System.out.println(s.[1]());
} [2] (NullPointerException e) {
    System.out.println("Null pointer caught");
} [3] {
    System.out.println("Always runs");
}

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Alength

Bcatch

Cfinally

Dsize

Attempts:

3 left

💡 Hint

Common Mistakes

Using size() which is not a String method

Using final instead of finally

Calling length() on a null string causes a NullPointerException, caught by catch, and the finally block always runs.