[Solved] What will be the output of this code?public class Example { public static void main(String[] args) { try { System.out.print("A"); throw new RuntimeException(); } catch (Exception e) { System.out.... | Java

Java - Exception Handling

What will be the output of this code?

public class Example {
    public static void main(String[] args) {
        try {
            System.out.print("A");
            throw new RuntimeException();
        } catch (Exception e) {
            System.out.print("B");
            return;
        } finally {
            System.out.print("C");
        }
        System.out.print("D");
    }
}

AABCD

BAC

CABC

DBCD

Step-by-Step Solution

Solution:

Step 1: Trace try block
Prints "A" then throws RuntimeException caught by catch.
Step 2: Execute catch block
Catch prints "B" and hits return, but finally still runs.
Step 3: Execute finally block
Finally prints "C" before method returns; "D" is never printed.
Final Answer:
ABC -> Option C
Quick Check:
finally runs even after return in catch [OK]

Quick Trick: finally runs even if catch returns [OK]

Common Mistakes:

Expecting 'D' to print after return
Ignoring finally block output
Assuming return skips finally

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More Java Quizzes

What will be the output of this code?

Step 1: Trace try block

Step 2: Execute catch block

Step 3: Execute finally block

Final Answer:

Quick Check:

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