[Solved] What will be the output of the following code?class Person { private String name = "Alice"; public String getName() { return name;... | Java

Java - Encapsulation

What will be the output of the following code?

class Person {
  private String name = "Alice";
  public String getName() { return name; }
}
public class Test {
  public static void main(String[] args) {
    Person p = new Person();
    System.out.println(p.name);
  }
}

ACompilation error

BAlice

Cnull

DRuntime error

Step-by-Step Solution

Solution:

Step 1: Analyze access to private variable
The variable 'name' is private in Person class, so it cannot be accessed directly outside the class.
Step 2: Check the print statement
System.out.println(p.name); tries to access private variable directly, causing a compilation error.
Final Answer:
Compilation error -> Option A
Quick Check:
Private variables cannot be accessed directly outside class [OK]

Quick Trick: Private variables cause compile error if accessed directly [OK]

Common Mistakes:

Assuming private variables print their value directly
Thinking it prints null by default
Expecting runtime error instead of compile error

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More Java Quizzes

What will be the output of the following code?

Step 1: Analyze access to private variable

Step 2: Check the print statement

Final Answer:

Quick Check:

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