[Solved] Consider this code snippet:public void process() throws IOException { try { throw new IOException("File error");... } }What is the effect of wrapping the checked exception in a RuntimeException? | Java

Java - Exception Handling

Consider this code snippet:

public void process() throws IOException {
  try {
    throw new IOException("File error");
  } catch (IOException e) {
    throw new RuntimeException(e);
  }
}

What is the effect of wrapping the checked exception in a RuntimeException?

ASwallows the original exception silently

BCauses compilation error due to throws declaration

CConverts checked exception to unchecked, no need to declare

DForces caller to catch RuntimeException

Step-by-Step Solution

Solution:

Step 1: Analyze exception wrapping
Wrapping IOException (checked) inside RuntimeException (unchecked) converts it to unchecked.
Step 2: Check throws declaration effect
Method declares throws IOException but actually throws RuntimeException, which does not require declaration.
Final Answer:
Converts checked exception to unchecked, no need to declare -> Option C
Quick Check:
Wrapping checked in unchecked removes declaration requirement [OK]

Quick Trick: Wrap checked exceptions in RuntimeException to avoid throws [OK]

Common Mistakes:

Expecting compilation error
Thinking original exception is lost
Assuming caller must catch RuntimeException

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More Java Quizzes

Consider this code snippet:

Step 1: Analyze exception wrapping

Step 2: Check throws declaration effect

Final Answer:

Quick Check:

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