[Solved] Identify the error in the following code:interface A { default void display() { System.out.println("A"); } } class B implements A { void display() { System.out.println("B"); } } | Java

Java - Interfaces

Identify the error in the following code:

interface A {
    default void display() {
        System.out.println("A");
    }
}
class B implements A {
    void display() {
        System.out.println("B");
    }
}

AInterface A cannot have default methods.

BDefault methods cannot be overridden.

CMethod display() in class B must be public.

DClass B must be declared abstract.

Step-by-Step Solution

Solution:

Step 1: Check method overriding rules
Methods overriding interface methods must have the same or broader access modifier.
Step 2: Identify access modifier mismatch
Interface methods are public by default; class B's display() is package-private, causing error.
Final Answer:
Method display() in class B must be public. -> Option C
Quick Check:
Overriding method access = Must be public [OK]

Quick Trick: Override interface methods with public access [OK]

Common Mistakes:

Using default (package) access instead of public
Thinking default methods cannot be overridden

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More Java Quizzes

Identify the error in the following code:

Step 1: Check method overriding rules

Step 2: Identify access modifier mismatch

Final Answer:

Quick Check:

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