[Solved] Identify the error in this code snippet:try { int x = 5 / 0; } catch (Exception e) { System.out.println("Error caught"); } catch (ArithmeticException e) { System.out.println("Arithmetic error"); } | Java

Java - Exception Handling

Identify the error in this code snippet:

try {
  int x = 5 / 0;
} catch (Exception e) {
  System.out.println("Error caught");
}
catch (ArithmeticException e) {
  System.out.println("Arithmetic error");
}

ASecond catch block is unreachable due to exception hierarchy.

BCatch blocks must be inside try block.

CNo error; code compiles and runs fine.

DMultiple catch blocks for same exception type cause compile error.

Step-by-Step Solution

Solution:

Step 1: Analyze catch block order
Catch for Exception is general and placed before ArithmeticException which is more specific.
Step 2: Understand unreachable catch blocks
Since Exception catches all exceptions, the second catch is unreachable, causing compile error.
Final Answer:
Second catch block is unreachable due to exception hierarchy. -> Option A
Quick Check:
General catch before specific = unreachable catch [OK]

Quick Trick: Place specific exceptions before general ones in catch [OK]

Common Mistakes:

Placing general catch before specific catch
Thinking catch blocks can be outside try
Assuming multiple catches for same exception allowed

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More Java Quizzes

Identify the error in this code snippet:

Step 1: Analyze catch block order

Step 2: Understand unreachable catch blocks

Final Answer:

Quick Check:

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