[Solved] Examine the error in this code:String s = "example"; s = s.toLowerCase(); s.charAt(2) = 'A'; — Ans: You cannot assign a character to s.charAt(2) because charAt() returns a value,... | Java

Java - Strings and String Handling

Examine the error in this code:

String s = "example";
s = s.toLowerCase();
s.charAt(2) = 'A';

AYou cannot assign a character to s.charAt(2) because charAt() returns a value, not a variable

BtoLowerCase() does not return a new string

CcharAt() can be used to set characters in a string

DThe code correctly changes the character at index 2

Step-by-Step Solution

Solution:

Step 1: Understand charAt()
charAt() returns a char value, not a reference that can be assigned to.
Step 2: String immutability
Strings are immutable, so individual characters cannot be changed directly.
Final Answer:
You cannot assign a character to s.charAt(2) because charAt() returns a value, not a variable -> Option A
Quick Check:
charAt() is read-only, cannot assign [OK]

Quick Trick: charAt() returns char value, not assignable [OK]

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