You want to print all command-line arguments separated by semicolons in Java. Which code snippet correctly does this inside main?

hard📝 Application Q8 of 15

Java - Command Line Arguments

You want to print all command-line arguments separated by semicolons in Java. Which code snippet correctly does this inside main?

ASystem.out.println(String.join(",", args));

for(int i=0; i<args.length; i++) {
  System.out.print(args[i]);
  if(i < args.length - 1) System.out.print(";");
}

Cfor(String arg : args) { System.out.println(arg + ";"); }

DSystem.out.println(args.toString());

Step-by-Step Solution

Solution:

Step 1: Understand requirement
Print all arguments separated by semicolons without trailing semicolon.
Step 2: Analyze options
for(int i=0; iSystem.out.println(String.join(",", args)); uses commas, not semicolons.
for(String arg : args) { System.out.println(arg + ";"); } prints each argument on new line with semicolon appended.
System.out.println(args.toString()); prints the array's default toString, not arguments.
Final Answer:
for(int i=0; i correctly prints arguments separated by semicolons.
Quick Check:
Loop with conditional separator avoids trailing delimiter [OK]

Quick Trick: Use loop with condition to avoid trailing separator [OK]

Common Mistakes:
Using String.join with wrong delimiter
Printing each argument on new line instead of inline
Printing array object instead of elements

Master "Command Line Arguments" in Java

9 interactive learning modes - each teaches the same concept differently

Learn Why Deep Visual Try Challenge Project Recall Time

Want More Practice?

15+ quiz questions · All difficulty levels · Free

Free Signup - Practice All Questions

More Java Quizzes

You want to print all command-line arguments separated by semicolons in Java. Which code snippet correctly does this inside main?

Step 1: Understand requirement

Step 2: Analyze options

Final Answer:

Quick Check:

Want More Practice?