Given an integer array arr of size 5 initialized as {2, 4, 6, 8, 10}, which code snippet correctly doubles each element's value?

hard📝 Application Q15 of 15

Java - Arrays

Given an integer array arr of size 5 initialized as {2, 4, 6, 8, 10}, which code snippet correctly doubles each element's value?

Afor(int i = 0; i < arr.length; i++) { arr[i] *= 2; }

Bfor(int i = 0; i <= arr.length; i++) { arr[i] = arr[i] * 2; }

Cfor(int i = 1; i < arr.length; i++) { arr[i] = arr[i] * 2; }

Dfor(int i = 0; i < arr.length - 1; i++) { arr[i] = arr[i] * 2; }

Step-by-Step Solution

Solution:

Step 1: Understand array length and loop bounds
The array length is 5, so valid indexes are 0 to 4. Loop must run from 0 to less than length.
Step 2: Evaluate each option's loop condition
for(int i = 0; i <= arr.length; i++) { arr[i] = arr[i] * 2; } uses i <= arr.length which causes out of bounds error at i=5. for(int i = 0; i < arr.length; i++) { arr[i] *= 2; } correctly uses i < arr.length. for(int i = 1; i < arr.length; i++) { arr[i] = arr[i] * 2; } starts at 1, missing index 0. for(int i = 0; i < arr.length - 1; i++) { arr[i] = arr[i] * 2; } stops at length-1, missing last element.
Final Answer:
for(int i = 0; i < arr.length; i++) { arr[i] *= 2; } -> Option A
Quick Check:
Loop from 0 to length-1 doubles all elements [OK]

Quick Trick: Use i < arr.length to avoid index errors [OK]

Common Mistakes:

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