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Find the error in this Java code simulating a use case step:

medium📝 Debug Q7 of 15
Java - Command Line Arguments
Find the error in this Java code simulating a use case step:
public class UseCase {
  public static void main(String[] args) {
    printMessage();
  }
  public static void printMessage() {
    System.out.println("Welcome to the system")
  }
}
AMethod printMessage must return a value
BClass name should be lowercase
Cmain method should not be static
DMissing semicolon after println statement
Step-by-Step Solution
Solution:
  1. Step 1: Check syntax of printMessage method

    The println statement is missing a semicolon at the end.
  2. Step 2: Validate other parts

    printMessage is void, so no return needed; main is correctly static; class name capitalization is valid.
  3. Final Answer:

    Missing semicolon after println statement -> Option D
  4. Quick Check:

    Statements must end with semicolon = B [OK]
Quick Trick: Every statement in Java ends with a semicolon [OK]
Common Mistakes:
  • Forgetting semicolon after print statements
  • Thinking void methods need return
  • Confusing static keyword usage

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