Why does accessing an array index outside its declared size cause an ArrayIndexOutOfBoundsException in Java?

hard📝 Conceptual Q10 of 15

Java - Arrays

Why does accessing an array index outside its declared size cause an ArrayIndexOutOfBoundsException in Java?

ABecause Java arrays automatically resize and the exception is a warning.

BBecause the JVM does not allow any array access.

CBecause Java arrays have fixed size and indices must be within 0 to length-1.

DBecause array elements are stored randomly in memory.

Step-by-Step Solution

Solution:

Step 1: Understand array size and indexing in Java
Arrays in Java have a fixed size set at creation, and valid indices range from 0 to length-1.
Step 2: Explain why out-of-range access causes exception
Accessing an index outside this range is invalid and causes ArrayIndexOutOfBoundsException to prevent unsafe memory access.
Final Answer:
Because Java arrays have fixed size and indices must be within 0 to length-1. -> Option C
Quick Check:
Fixed size arrays enforce valid index range [OK]

Quick Trick: Array indices must be within declared size limits [OK]

Common Mistakes:

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