[Solved] Find the error in this code snippet:String s = "Example"; if(s.equalsIgnoreCase = "example") { System.out.println("Match"); } | Java

Java - Strings and String Handling

Find the error in this code snippet:

String s = "Example";
if(s.equalsIgnoreCase = "example") {
  System.out.println("Match");
}

AequalsIgnoreCase is not a method

BAssignment operator used instead of method call

CMissing semicolon after if condition

DString comparison should use == operator

Step-by-Step Solution

Solution:

Step 1: Analyze equalsIgnoreCase usage
equalsIgnoreCase is a method and must be called with parentheses.
Step 2: Identify operator mistake
Code uses '=' (assignment) instead of '()' method call.
Final Answer:
Assignment operator used instead of method call -> Option B
Quick Check:
Use equalsIgnoreCase() with parentheses, not '=' [OK]

Quick Trick: Call equalsIgnoreCase() with parentheses [OK]

Common Mistakes:

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