Given int[] nums = {10, 20, 30, 40, 50};, which loop correctly prints all elements using the array's length property?

hard📝 Application Q8 of 15

Java - Arrays

Given int[] nums = {10, 20, 30, 40, 50};, which loop correctly prints all elements using the array's length property?

Afor(int i = 1; i <= nums.length; i++) { System.out.print(nums[i] + " "); }

Bfor(int i = 0; i < nums.length; i++) { System.out.print(nums[i] + " "); }

Cfor(int i = 0; i <= nums.length; i++) { System.out.print(nums[i] + " "); }

Dfor(int i = 1; i < nums.length; i++) { System.out.print(nums[i] + " "); }

Step-by-Step Solution

Solution:

Step 1: Understand array indexing
Array indices start at 0 and go up to length - 1.
Step 2: Analyze each option
for(int i = 0; i < nums.length; i++) { System.out.print(nums[i] + " "); } correctly loops from 0 to nums.length - 1. Options B and D start at 1, missing the first element. for(int i = 0; i <= nums.length; i++) { System.out.print(nums[i] + " "); } goes to nums.length, causing an IndexOutOfBoundsException.
Final Answer:
for(int i = 0; i < nums.length; i++) { System.out.print(nums[i] + " "); } -> Option B
Quick Check:
Loop from 0 to length-1 to access all elements. [OK]

Quick Trick: Loop from 0 to length-1 for arrays. [OK]

Common Mistakes:

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