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iOS Swiftmobile~5 mins

Protocols in iOS Swift

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Introduction

Protocols help you define a set of rules or actions that different parts of your app can follow. They make your code organized and easy to change.

When you want different objects to share common behavior without sharing code.
When you want to make sure a class or struct has certain functions or properties.
When you want to write flexible code that can work with many types.
When you want to separate what something does from how it does it.
Syntax
iOS Swift
protocol ProtocolName {
    func someFunction()
    var someProperty: String { get set }
}

Protocols list methods and properties without giving their code.

Classes, structs, or enums can adopt protocols by implementing the required parts.

Examples
A simple protocol requiring a drive() function.
iOS Swift
protocol Drivable {
    func drive()
}
This protocol requires a read-only name property.
iOS Swift
protocol Named {
    var name: String { get }
}
A struct adopting Drivable and providing the drive() function.
iOS Swift
struct Car: Drivable {
    func drive() {
        print("Car is driving")
    }
}
Sample App

This program defines a protocol Greetable with a greet() function. The Person class adopts it and implements greet() to say hello with a name.

iOS Swift
protocol Greetable {
    func greet()
}

class Person: Greetable {
    var name: String
    init(name: String) {
        self.name = name
    }
    func greet() {
        print("Hello, my name is \(name)")
    }
}

let person = Person(name: "Anna")
person.greet()
OutputSuccess
Important Notes

Protocols do not contain code, only the rules to follow.

Use protocols to write flexible and reusable code.

Multiple protocols can be adopted by one class or struct.

Summary

Protocols define a blueprint of methods and properties.

Classes, structs, and enums can adopt protocols by implementing required parts.

Protocols help keep code organized and flexible.

Practice

(1/5)
1. What is the main purpose of a protocol in Swift?
easy
A. To create a new class with default behavior
B. To define a blueprint of methods and properties that a type must implement
C. To store data persistently on the device
D. To handle user interface layout automatically

Solution

  1. Step 1: Understand what a protocol defines

    A protocol specifies methods and properties that a type must implement, acting as a blueprint.
  2. Step 2: Differentiate from other concepts

    Protocols do not create classes or store data; they only define requirements.
  3. Final Answer:

    To define a blueprint of methods and properties that a type must implement -> Option B
  4. Quick Check:

    Protocol purpose = blueprint [OK]
Hint: Protocols define required methods and properties [OK]
Common Mistakes:
  • Confusing protocols with classes
  • Thinking protocols store data
  • Assuming protocols handle UI layout
2. Which of the following is the correct syntax to declare a protocol named Drivable in Swift?
easy
A. struct Drivable { func drive() }
B. class Drivable { func drive() }
C. func protocol Drivable() { drive() }
D. protocol Drivable { func drive() }

Solution

  1. Step 1: Identify correct protocol declaration syntax

    Protocols are declared with the keyword protocol followed by the name and curly braces.
  2. Step 2: Check method declaration inside protocol

    Methods inside protocols are declared without implementation, just the signature.
  3. Final Answer:

    protocol Drivable { func drive() } -> Option D
  4. Quick Check:

    Protocol syntax = keyword 'protocol' + name + method signatures [OK]
Hint: Use 'protocol' keyword, not class or struct [OK]
Common Mistakes:
  • Using class or struct instead of protocol
  • Adding method implementation inside protocol
  • Incorrect keyword order
3. Consider this Swift code:
protocol Greetable {
  func greet() -> String
}

struct Person: Greetable {
  func greet() -> String {
    return "Hello!"
  }
}

let p = Person()
print(p.greet())

What will be printed when this code runs?
medium
A. Hello!
B. greet()
C. Error: Missing protocol implementation
D. nil

Solution

  1. Step 1: Check protocol and struct conformance

    The struct Person adopts Greetable and implements the required greet() method returning "Hello!".
  2. Step 2: Understand the print statement output

    Calling p.greet() returns "Hello!", which is printed.
  3. Final Answer:

    Hello! -> Option A
  4. Quick Check:

    Implemented method returns "Hello!" [OK]
Hint: Implemented protocol methods run normally [OK]
Common Mistakes:
  • Expecting protocol name printed
  • Thinking missing implementation error occurs
  • Assuming nil is printed
4. What is wrong with this Swift code?
protocol Runnable {
  func run()
}

struct Athlete: Runnable {
  // Missing run() implementation
}
medium
A. No error, code is valid
B. Error: run() must have a return type
C. Error: Athlete does not implement required method run()
D. Error: Protocol Runnable cannot be adopted by struct

Solution

  1. Step 1: Check protocol requirements

    The protocol Runnable requires a method run() with no return value.
  2. Step 2: Verify struct conformance

    The struct Athlete adopts Runnable but does not implement run(), causing a compile error.
  3. Final Answer:

    Error: Athlete does not implement required method run() -> Option C
  4. Quick Check:

    Missing required method causes error [OK]
Hint: All protocol methods must be implemented [OK]
Common Mistakes:
  • Assuming structs can't adopt protocols
  • Thinking missing method is allowed
  • Expecting run() to require return type
5. You want to create a protocol Vehicle with a property speed that can be read and set. Which of these protocol declarations is correct?
hard
A. protocol Vehicle { var speed: Int { get set } }
B. protocol Vehicle { var speed: Int }
C. protocol Vehicle { func speed() -> Int }
D. protocol Vehicle { let speed: Int }

Solution

  1. Step 1: Understand property requirements in protocols

    To require a property to be readable and writable, use { get set } in the protocol.
  2. Step 2: Analyze each option

    protocol Vehicle { var speed: Int { get set } } correctly declares speed as a variable property with get set. protocol Vehicle { var speed: Int } misses get set, so it's read-only. protocol Vehicle { func speed() -> Int } declares a method, not a property. protocol Vehicle { let speed: Int } uses let, which is not allowed in protocols.
  3. Final Answer:

    protocol Vehicle { var speed: Int { get set } } -> Option A
  4. Quick Check:

    Writable property = var with get set [OK]
Hint: Use 'var' with { get set } for read-write properties [OK]
Common Mistakes:
  • Using 'let' in protocol properties
  • Omitting { get set } for writable properties
  • Confusing methods with properties
Recommended

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10 questions~5 mineasy hard