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Intro to Computingfundamentals~10 mins

Sorting algorithms (bubble, selection) in Intro to Computing - Draw & Build Visually

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Draw a flowchart for the Bubble Sort algorithm to sort the list [5, 3, 8, 4] in ascending order.

10 minutes
Hint 1
Hint 2
Hint 3
Grading Criteria
Start and End oval symbols present
Initialization steps for counters (i and j) included
Decision diamonds used for comparisons (j < length-1-i and list[j] > list[j+1])
Swapping step clearly shown when condition is true
Loop back arrows correctly connect decisions and processes
Swapped flag used to detect if sorting is complete
Flowchart covers all passes until no swaps occur
Solution
j
j+1
j
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j
j+1
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This flowchart shows the Bubble Sort algorithm working on the list [5, 3, 8, 4].

1. Start with i = 0, which tracks how many passes have been done.

2. Set a flag swapped to false to check if any swaps happen in this pass.

3. Use j to compare adjacent elements from the start to the end minus the sorted part.

4. If list[j] is greater than list[j+1], swap them and set swapped to true.

5. Increment j and repeat until the end of the unsorted part.

6. If no swaps happened (swapped is false), the list is sorted and the algorithm ends.

7. Otherwise, increment i and repeat the process for the next pass.

This process continues until the list is fully sorted in ascending order.

Variations - 2 Challenges
[intermediate] Draw a flowchart for the Selection Sort algorithm to sort the list [7, 2, 9, 1] in ascending order.
[advanced] Draw a flowchart for Bubble Sort to sort the list [4, 6, 2, 9, 1] in descending order.

Practice

(1/5)
1. Which of the following best describes how bubble sort works?
easy
A. It repeatedly swaps neighboring items to move the largest to the end.
B. It finds the smallest item and places it at the start each time.
C. It divides the list into halves and sorts each half separately.
D. It uses a pivot to partition the list into smaller parts.

Solution

  1. Step 1: Understand bubble sort's swapping method

    Bubble sort compares neighbors and swaps them if out of order, pushing the largest to the end.
  2. Step 2: Compare with other sorting methods

    Selection sort finds smallest items, quicksort uses pivots, so bubble sort matches It repeatedly swaps neighboring items to move the largest to the end.
  3. Final Answer:

    It repeatedly swaps neighboring items to move the largest to the end. -> Option A
  4. Quick Check:

    Bubble sort = neighbor swaps [OK]
Hint: Bubble sort swaps neighbors to push largest out [OK]
Common Mistakes:
  • Confusing bubble sort with selection sort
  • Thinking bubble sort uses pivots
  • Assuming bubble sort divides list into halves
2. Which of the following is the correct way to start a selection sort on a list named arr in Python?
easy
A. for i in range(1, len(arr)+1):
B. for i in arr:
C. while i < len(arr):
D. for i in range(len(arr)):

Solution

  1. Step 1: Identify the loop for selection sort

    Selection sort uses an index loop from 0 to length-1 to select positions.
  2. Step 2: Check Python syntax correctness

    Using for i in range(len(arr)): correctly loops over indices; others are incorrect or off-by-one.
  3. Final Answer:

    for i in range(len(arr)): -> Option D
  4. Quick Check:

    Selection sort loops over indices 0 to n-1 [OK]
Hint: Use range(len(arr)) to loop over list indices [OK]
Common Mistakes:
  • Using for i in arr (loops over values, not indices)
  • Using while without initializing i
  • Using range starting at 1 causing off-by-one errors
3. What is the output of the following bubble sort pass on the list [4, 2, 5, 1]?
Initial list: [4, 2, 5, 1]
Pass 1: Compare and swap neighbors if needed
medium
A. [2, 4, 5, 1]
B. [2, 4, 1, 5]
C. [4, 2, 1, 5]
D. [1, 2, 4, 5]

Solution

  1. Step 1: Perform neighbor comparisons and swaps

    Compare 4 & 2: swap -> [2, 4, 5, 1]; compare 4 & 5: no swap; compare 5 & 1: swap -> [2, 4, 1, 5]
  2. Step 2: Confirm final list after pass 1

    After one pass, largest number 5 is bubbled to the end, list is [2, 4, 1, 5]
  3. Final Answer:

    [2, 4, 1, 5] -> Option B
  4. Quick Check:

    Bubble pass 1 swaps neighbors -> [2, 4, 1, 5] [OK]
Hint: Swap neighbors if left is bigger, largest moves right [OK]
Common Mistakes:
  • Not swapping 5 and 1 at the end
  • Swapping 4 and 5 incorrectly
  • Assuming full sort after one pass
4. The following selection sort code has a bug. What is the error?
arr = [3, 1, 4]
for i in range(len(arr)):
    min_idx = i
    for j in range(i+1, len(arr)):
        if arr[j] < arr[min_idx]:
            min_idx = j
    arr[i], arr[min_idx] = arr[min_idx], arr[i]
print(arr)
medium
A. The inner loop should start from i, not i+1
B. The swap line is incorrect; it should not swap
C. No bug; the code correctly sorts the list
D. min_idx should be initialized outside the outer loop

Solution

  1. Step 1: Analyze the selection sort logic

    min_idx starts at i, inner loop finds smallest element index after i, then swaps with i.
  2. Step 2: Verify correctness with example

    For arr=[3,1,4], code finds min at index 1 and swaps with index 0, resulting in sorted list [1,3,4].
  3. Final Answer:

    No bug; the code correctly sorts the list -> Option C
  4. Quick Check:

    Selection sort code correct as given [OK]
Hint: Check if code sorts example list correctly [OK]
Common Mistakes:
  • Thinking inner loop must start at i
  • Believing swap line is wrong
  • Misunderstanding min_idx initialization
5. You have a list [7, 3, 5, 2, 9]. After two full passes of selection sort, what will the list look like?
hard
A. [2, 3, 7, 5, 9]
B. [3, 2, 5, 7, 9]
C. [2, 3, 5, 7, 9]
D. [7, 3, 5, 2, 9]

Solution

  1. Step 1: Perform first pass of selection sort

    Find smallest in [7, 3, 5, 2, 9] is 2 at index 3; swap with index 0 -> [2, 3, 5, 7, 9]
  2. Step 2: Perform second pass on sublist from index 1 [3, 5, 7, 9]

    Find smallest is 3 at index 1; swap with index 1 (no change) -> [2, 3, 5, 7, 9]
  3. Final Answer:

    [2, 3, 7, 5, 9] -> Option A
  4. Quick Check:

    Selection sort places smallest at start each pass [OK]
Hint: Selection sort fixes one smallest item per pass [OK]
Common Mistakes:
  • Assuming list is unchanged after passes
  • Mixing bubble sort behavior with selection sort
  • Swapping incorrectly during passes