Conditional logic (if-then decisions) in Intro to Computing - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to check if a number is positive.

Intro to Computing

if number [1] 0:
    print("Positive number")

Drag options to blanks, or click blank then click option'

A<

B>

C==

D<=

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>' will check for negative numbers.

Using '==' checks only if the number is exactly zero.

The condition number > 0 checks if the number is greater than zero, meaning it is positive.

2fill in blank

medium

Complete the code to print "Even" if the number is divisible by 2.

Intro to Computing

if number [1] 2 == 0:
    print("Even")

Drag options to blanks, or click blank then click option'

A//

B+

C%

D*

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' or '*' instead of '%' will not check divisibility.

Using '//' gives the quotient, not the remainder.

The modulus operator % gives the remainder of division. If number % 2 == 0, the number is even.

3fill in blank

hard

Fix the error in the code to check if a number is negative.

Intro to Computing

if number [1] 0:
    print("Negative number")

Drag options to blanks, or click blank then click option'

A>=

B>

C==

D<

Attempts:

3 left

💡 Hint

Common Mistakes

Using '>' checks for positive numbers instead.

Using '==' checks only if the number is zero.

The condition number < 0 correctly checks if the number is less than zero, meaning it is negative.

4fill in blank

hard

Fill in the blank to print "Adult" if age is 18 or older.

Intro to Computing

if age [1] 18:
    print("Adult")

Drag options to blanks, or click blank then click option'

A>=

B<

Cand

Dor

Attempts:

3 left

💡 Hint

Common Mistakes

Using '<' instead of '>=' will check the wrong condition.

Using 'and' or 'or' incorrectly can cause logic errors.

The condition age >= 18 checks if the age is 18 or older.

5fill in blank

hard

Fill all three blanks to create a dictionary of words and their lengths for words longer than 3 characters.

Intro to Computing

lengths = [1]: [2] for [3] in words if len([3]) > 3

Drag options to blanks, or click blank then click option'

Aword

Blen(word)

Dw

Attempts:

3 left

💡 Hint

Common Mistakes

Using different variable names inconsistently.

Putting the length function in the wrong place.

This dictionary comprehension uses word as the variable to iterate over words. The key is word itself, and the value is len(word), but only for words longer than 3 characters.