Given a list of numbers, how can you efficiently find if any number is greater than 100 using Python?

hard🚀 Application Q9 of Q15

Intro to Computing - How Files and Folders Organize Data

AUse any() with a condition checking > 100

BUse index() to find 100

CSort the list and check last element

DUse count() to count numbers > 100

Step-by-Step Solution

Solution:

Step 1: Understand the task
We want to check if any number is greater than 100, not find exact position or count.
Step 2: Evaluate options
any() with a condition returns True if any element meets it. index() and count() don't work for conditions. Sorting then checking last element works but is less efficient.
Final Answer:
Use any() with a condition checking > 100 -> Option A
Quick Check:
any() checks condition efficiently [OK]

Quick Trick: Use any() to test conditions on list elements [OK]

Common Mistakes:

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