Data compression basics in Intro to Computing - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to assign the variable that stores the original data size.

Intro to Computing

original_size = [1]

Drag options to blanks, or click blank then click option'

Alen(data)

Bcompression_ratio

Cdecompressed_data

Dcompressed_data

Attempts:

3 left

💡 Hint

Common Mistakes

Using the compressed data variable instead of the original data.

Confusing compression ratio with data size.

The len(data) function returns the size of the original data in bytes or characters.

2fill in blank

medium

Complete the code to calculate the compression ratio correctly.

Intro to Computing

compression_ratio = [1] / original_size

Drag options to blanks, or click blank then click option'

Acompressed_size

Boriginal_size

Cdecompressed_size

Ddata_length

Attempts:

3 left

💡 Hint

Common Mistakes

Dividing original size by compressed size instead of the other way.

Using decompressed size which is not defined.

The compression ratio is calculated by dividing the compressed data size by the original data size.

3fill in blank

hard

Fix the error in the code to decompress data using the correct method.

Intro to Computing

decompressed_data = compressed_data.[1]()

Drag options to blanks, or click blank then click option'

Acompress

Bdecompress

Cencode

Ddecode

Attempts:

3 left

💡 Hint

Common Mistakes

Using 'compress' which compresses data again.

Using 'encode' or 'decode' which are for text encoding.

The method to restore original data from compressed data is decompress().

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps each word to its compressed length if the length is less than 5.

Intro to Computing

{word: len(word)[1] for word in words if len(word) [2] 5}

Drag options to blanks, or click blank then click option'

A**2

B>

C<

D+1

Attempts:

3 left

💡 Hint

Common Mistakes

Using '+' instead of '**' for squaring.

Using '>' instead of '<' in the condition.

The first blank uses **2 to square the length, and the second blank uses < to filter words shorter than 5 characters.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps the uppercase word to its length if the length is greater than 3.

Intro to Computing

result = {{ [1]: [2] for word in words if len(word) [3] 3 }}

Drag options to blanks, or click blank then click option'

Aword.upper()

Blen(word)

C>

Dword.lower()

Attempts:

3 left

💡 Hint

Common Mistakes

Using lowercase instead of uppercase for keys.

Using '<' instead of '>' in the condition.

The dictionary keys are uppercase words using word.upper(), values are their lengths with len(word), and the filter uses > to select words longer than 3 characters.