Binary number system in Intro to Computing - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to convert the decimal number 5 to binary using the built-in function.

Intro to Computing

binary_value = bin([1])

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A8

B10

C2

D5

Attempts:

3 left

💡 Hint

Common Mistakes

Using a binary number instead of a decimal number inside bin()

Confusing the base of the number

The bin() function converts a decimal number to its binary representation. Here, 5 is the decimal number to convert.

2fill in blank

medium

Complete the code to convert the binary string '1010' to a decimal number.

Intro to Computing

decimal_value = int('[1]', 2)

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A1010

B10

C2

D1001

Attempts:

3 left

💡 Hint

Common Mistakes

Passing a decimal number instead of a string

Forgetting to specify base 2

The int() function converts a string in a given base to a decimal integer. Here, '1010' is the binary string to convert.

3fill in blank

hard

Fix the error in the code to correctly convert the decimal number 12 to binary without the '0b' prefix.

Intro to Computing

binary_str = bin(12)[1]

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A[1:]

B[2:]

C.substring(2)

D.slice(2)

Attempts:

3 left

💡 Hint

Common Mistakes

Using JavaScript string methods like .slice() or .substring() in Python

Using incorrect slicing syntax

The bin() function returns a string starting with '0b'. Using slicing [2:] removes the first two characters.

4fill in blank

hard

Fill both blanks to create a dictionary comprehension that maps decimal numbers 1 to 5 to their binary strings without the '0b' prefix.

Intro to Computing

binary_dict = {num: bin(num)[1] for num in range(1, 6) if num [2] 3}

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A[2:]

B>

C<

D==

Attempts:

3 left

💡 Hint

Common Mistakes

Using incorrect slicing syntax

Using wrong comparison operators

The slicing [2:] removes the '0b' prefix from the binary string. The condition num > 3 filters numbers greater than 3.

5fill in blank

hard

Fill all three blanks to create a dictionary comprehension that maps uppercase hexadecimal digits to their decimal values, including only digits greater than 9.

Intro to Computing

hex_dict = { [1]: int([2], 16) for [3] in ['A', 'B', 'C', 'D', 'E', 'F'] if int([3], 16) > 9 }

Drag options to blanks, or click blank then click option'

Adigit

Dvalue

Attempts:

3 left

💡 Hint

Common Mistakes

Using different variable names inconsistently

Forgetting to specify base 16 in int()

We use digit as the variable name for keys and values. The comprehension iterates over the list of hex digits and converts each to decimal using int(digit, 16). The condition filters digits with decimal value greater than 9.