Challenge - 5 Problems
Web Crawler Mastery
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Test your skills under time pressure!
❓ Architecture
intermediate2:00remaining
Identify the main components of a web crawler architecture
Which of the following lists correctly represents the essential components of a scalable web crawler system?
Attempts:
2 left
💡 Hint
Think about the components that handle URL management, downloading pages, and storing data.
✗ Incorrect
A web crawler needs to manage URLs to visit (URL Frontier), download pages (Fetcher), extract links and content (Parser), filter URLs to avoid duplicates or unwanted sites (URL Filter), and store the data (Storage).
❓ scaling
intermediate2:00remaining
Scaling the URL Frontier in a distributed crawler
What is the best approach to scale the URL Frontier component to handle billions of URLs efficiently?
Attempts:
2 left
💡 Hint
Consider how to avoid bottlenecks and balance load across servers.
✗ Incorrect
Partitioning URLs by domain and distributing queues allows parallel processing and avoids a single bottleneck, making the system scalable.
❓ tradeoff
advanced2:00remaining
Tradeoffs in politeness and crawling speed
Which option best describes the tradeoff between politeness (respecting website rules) and crawling speed in a web crawler?
Attempts:
2 left
💡 Hint
Think about how respecting website rules affects how fast you can crawl.
✗ Incorrect
Respecting politeness means adding delays between requests to the same site, which reduces crawling speed but avoids overloading servers or getting banned.
🧠 Conceptual
advanced2:00remaining
Handling duplicate content in web crawling
What is the most effective method to detect and avoid storing duplicate pages in a web crawler system?
Attempts:
2 left
💡 Hint
Think about a fast way to check if content is the same without storing everything twice.
✗ Incorrect
Using hash functions like MD5 or SHA on page content allows quick comparison to detect duplicates without storing full content multiple times.
❓ estimation
expert2:00remaining
Estimating storage needs for a large-scale web crawler
If a web crawler downloads 1 billion pages per year, each averaging 500 KB, what is the approximate storage needed per year (in terabytes) to store raw pages without compression?
Attempts:
2 left
💡 Hint
Calculate total bytes: pages × size, then convert to terabytes (1 TB = 10^12 bytes).
✗ Incorrect
1 billion pages × 500 KB = 10^9 × 500 × 10^3 bytes = 5 × 10^14 bytes. 5 × 10^14 / 10^12 = 500 TB.
