Load balancing algorithms (round robin, least connections) in HLD - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to select the next server using round robin.

HLD

next_server = servers[[1] % len(servers)]

Drag options to blanks, or click blank then click option'

Acurrent_index

Bserver_count

Crandom_index

Dmax_connections

Attempts:

3 left

💡 Hint

Common Mistakes

Using random index instead of cycling

Using max connections for round robin

Round robin selects the next server by cycling through the list using the current index modulo the number of servers.

2fill in blank

medium

Complete the code to find the server with the least connections.

HLD

least_loaded_server = min(servers, key=lambda s: s.[1])

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Aload

Bcapacity

Cconnections

Dlatency

Attempts:

3 left

💡 Hint

Common Mistakes

Using load or capacity instead of connections

Using latency which is unrelated

Least connections algorithm picks the server with the smallest number of active connections.

3fill in blank

hard

Fix the error in the round robin index update.

HLD

current_index = (current_index [1] 1) % len(servers)

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A/

B-

C*

D+

Attempts:

3 left

💡 Hint

Common Mistakes

Using subtraction which moves backward

Using multiplication or division which is incorrect

To move to the next server, increment the index by 1 and wrap around using modulo.

4fill in blank

hard

Fill both blanks to create a dictionary of servers with their connection counts, filtering servers with less than 10 connections.

HLD

{server.id: server.[1] for server in servers if server.[2] < 10}

Drag options to blanks, or click blank then click option'

Aconnections

Bload

Dcapacity

Attempts:

3 left

💡 Hint

Common Mistakes

Using different attributes for mapping and filtering

Using load or capacity instead of connections

This dictionary comprehension maps server IDs to their connection counts, filtering only servers with fewer than 10 connections.

5fill in blank

hard

Fill all three blanks to implement a function that selects a server using least connections algorithm.

HLD

def select_server(servers):
    return min(servers, key=lambda [1]: [2].[3])

Drag options to blanks, or click blank then click option'

Aserver

Bs

Dconnections

Attempts:

3 left

💡 Hint

Common Mistakes

Using inconsistent variable names

Accessing wrong attributes

The function uses a lambda with parameter 's' to find the server with the minimum number of connections.