What does LRU stand for in cache eviction policies?
LRU stands for Least Recently Used. It evicts the cache item that has not been used for the longest time.
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beginner
Explain LFU cache eviction policy.
LFU stands for Least Frequently Used. It removes the cache item that has been accessed the fewest times.
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beginner
What is TTL in cache eviction and how does it work?
TTL means Time To Live. It sets a fixed time limit for cache items. After this time, the item expires and is removed.
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intermediate
Which cache eviction policy is best when recent data is more important?
LRU is best when recent data is more important because it keeps the most recently used items in cache.
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intermediate
Why might LFU be less effective in some scenarios compared to LRU?
LFU can keep rarely used but frequently accessed old data, which may waste cache space. LRU adapts better to changing access patterns.
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Which cache eviction policy removes the item that was used least recently?
ALRU
BLFU
CTTL
DRandom
✗ Incorrect
LRU removes the least recently used item to make space.
What does LFU prioritize when evicting cache items?
AItems with the oldest timestamp
BItems used most recently
CItems used least frequently
DItems with the shortest TTL
✗ Incorrect
LFU evicts items that have been accessed the fewest times.
TTL cache eviction is based on which factor?
AFrequency of access
BRecency of access
CCache size limit
DTime elapsed since insertion
✗ Incorrect
TTL evicts items after a fixed time since they were added.
Which eviction policy is best for caching session data that expires after a fixed time?
ATTL
BLRU
CLFU
DRandom
✗ Incorrect
TTL is ideal for data that should expire after a set duration.
If a cache keeps frequently accessed old data but ignores recent data, which policy might it be using?
ALRU
BLFU
CTTL
DFIFO
✗ Incorrect
LFU can keep old frequently accessed data, ignoring recent usage.
Describe the differences between LRU, LFU, and TTL cache eviction policies.
Think about how each policy decides which item to remove.
You got /4 concepts.
Explain when you would choose LRU over LFU or TTL for cache eviction in a system.
Consider what kind of data your system uses most.
You got /4 concepts.
Practice
(1/5)
1. Which cache eviction policy removes the data that was used the longest time ago?
easy
A. Random Replacement
B. Least Frequently Used (LFU)
C. Time To Live (TTL)
D. Least Recently Used (LRU)
Solution
Step 1: Understand LRU policy
LRU removes the cache entry that was accessed the longest time ago, prioritizing recent usage.
Step 2: Compare with other policies
LFU removes least used items by frequency, TTL removes expired items by time, Random Replacement is arbitrary.
Final Answer:
Least Recently Used (LRU) -> Option D
Quick Check:
Oldest access time = LRU [OK]
Hint: LRU = remove oldest used data [OK]
Common Mistakes:
Confusing LRU with LFU
Thinking TTL removes based on usage
Assuming random removal is LRU
2. Which of the following is a correct description of the TTL cache eviction policy?
easy
A. Removes data after a fixed expiration time
B. Removes the least recently used data
C. Removes the least frequently used data
D. Removes data randomly when cache is full
Solution
Step 1: Define TTL policy
TTL (Time To Live) removes cache entries after their set expiration time passes.
Step 2: Contrast with other policies
LRU removes oldest used, LFU removes least used by frequency, random is arbitrary.
Final Answer:
Removes data after a fixed expiration time -> Option A
Quick Check:
TTL = expiration time removal [OK]
Hint: TTL means data expires after set time [OK]
Common Mistakes:
Mixing TTL with LRU or LFU
Thinking TTL depends on usage frequency
Assuming TTL removes randomly
3. Consider a cache with the following access pattern: keys A, B, A, C, B, A. Using LFU eviction, which key will be evicted when the cache is full and a new key D is added?
medium
A. Key C
B. Key A
C. Key B
D. Key D
Solution
Step 1: Count frequency of each key
Key A accessed 3 times, B accessed 2 times, C accessed 1 time.
Step 2: Identify LFU eviction candidate
LFU removes the least frequently used key, which is C with frequency 1.
Final Answer:
Key C -> Option A
Quick Check:
Lowest frequency = C [OK]
Hint: LFU evicts lowest frequency key [OK]
Common Mistakes:
Evicting most recent key instead of least frequent
Confusing frequency with recency
Evicting key D which is new
4. A cache using TTL eviction is not removing expired entries as expected. Which of the following is the most likely cause?
medium
A. The TTL value is set too low
B. The cache uses LRU instead of TTL
C. The cache does not check expiration before access
D. The cache size is too large
Solution
Step 1: Understand TTL eviction mechanism
TTL eviction requires checking if entries have expired before returning or during cleanup.
Step 2: Identify why expired entries remain
If cache does not check expiration on access or cleanup, expired entries stay indefinitely.
Final Answer:
The cache does not check expiration before access -> Option C
Quick Check:
Expiration check missing = no TTL eviction [OK]
Hint: TTL needs expiration checks to remove entries [OK]
Common Mistakes:
Assuming low TTL causes no eviction
Confusing TTL with LRU behavior
Thinking cache size affects TTL eviction
5. You are designing a cache for a news website where articles are frequently accessed shortly after publishing but rarely after a few days. Which eviction policy is best suited to keep fresh content while removing stale data efficiently?
hard
A. Least Recently Used (LRU)
B. Time To Live (TTL)
C. Random Replacement
D. Least Frequently Used (LFU)
Solution
Step 1: Analyze data usage pattern
Articles are popular shortly after publishing, then become stale after days.
Step 2: Match eviction policy to pattern
TTL removes data after expiration time, ideal for removing stale articles automatically.
Step 3: Compare with other policies
LRU and LFU focus on usage, but TTL ensures freshness by time. Random is inefficient.
Final Answer:
Time To Live (TTL) -> Option B
Quick Check:
Freshness by expiration time = TTL [OK]
Hint: Use TTL for time-based freshness eviction [OK]
Common Mistakes:
Choosing LRU or LFU ignoring data staleness
Assuming random eviction is efficient
Not considering time-based expiration
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