Input type for complex arguments in GraphQL - Interactive Code Practice

Practice - 5 Tasks

1fill in blank

easy

Complete the code to define an input type for a user with name and age fields.

GraphQL

input UserInput { name: String[1] }

Drag options to blanks, or click blank then click option'

A?

B!

C$

D#

Attempts:

3 left

💡 Hint

Common Mistakes

Using ? which is not valid in GraphQL type definitions.

Omitting the exclamation mark when the field should be required.

The exclamation mark ! means the field is required (non-nullable).

2fill in blank

medium

Complete the code to add an age field of type Int to the input type.

GraphQL

input UserInput { age: [1] }

Drag options to blanks, or click blank then click option'

AInt

BFloat

CString

DBoolean

Attempts:

3 left

💡 Hint

Common Mistakes

Using Float which allows decimals.

Using String which is for text.

The Int type is used for integer numbers in GraphQL.

3fill in blank

hard

Fix the error in the mutation argument by completing the input type usage.

GraphQL

type Mutation { createUser(input: [1]): User }

Drag options to blanks, or click blank then click option'

AUser

BUserType

CUserInput

DInputUser

Attempts:

3 left

💡 Hint

Common Mistakes

Using the output type User instead of the input type.

Using incorrect input type names.

The argument should use the input type UserInput defined for complex inputs.

4fill in blank

hard

Complete the code to define an input type with a required name and optional email.

GraphQL

input ContactInput { name: String[1], email: String }

Drag options to blanks, or click blank then click option'

A!

B?

Attempts:

3 left

💡 Hint

Common Mistakes

Marking optional fields as required.

Using ? which is invalid in GraphQL.

The name is required so it uses !. The email is optional so it has no exclamation mark.

5fill in blank

hard

Fill all three blanks to define a mutation that takes a required input and returns a User type.

GraphQL

type Mutation { addUser(input: [1][2]): [3] }

Drag options to blanks, or click blank then click option'

AUserInput

B!

CUser

DInputUser

Attempts:

3 left

💡 Hint

Common Mistakes

Omitting the exclamation mark for required input.

Using the input type as return type.

The mutation argument uses the required input type UserInput! and returns the User type.