Why arrays are needed in Go - Test Your Understanding

Practice - 5 Tasks

1fill in blank

easy

Complete the code to declare an array of 5 integers.

Go

[1] numbers [5]int

Drag options to blanks, or click blank then click option'

A:=

Bvar

Carray

D=

Attempts:

3 left

💡 Hint

Common Mistakes

Using := instead of var for array declaration

Trying to assign an array with = without var keyword

In Go, to declare an array variable, you use var followed by the name, then the type. Just var numbers [5]int is correct. Here, the blank is for the declaration keyword, so the correct answer is var.

2fill in blank

medium

Complete the code to assign the value 10 to the first element of the array.

Go

numbers[[1]] = 10

Drag options to blanks, or click blank then click option'

A5

B-1

C0

D1

Attempts:

3 left

💡 Hint

Common Mistakes

Using 1 as the first index

Using negative indexes

Arrays in Go are zero-indexed, which means the first element is at index 0. So to assign 10 to the first element, use numbers[0] = 10.

3fill in blank

hard

Fix the error in the code to print the length of the array.

Go

fmt.Println(len([1]))

Drag options to blanks, or click blank then click option'

Anumbers

Bnumbers()

Clen(numbers)

Dnumbers.len

Attempts:

3 left

💡 Hint

Common Mistakes

Using numbers() which is a function call

Trying to access length as a property like numbers.len

The len function in Go takes the array variable directly without parentheses. So len(numbers) is correct, but inside fmt.Println you just pass len(numbers). Here, the blank is for the argument inside len(), so it should be numbers.

4fill in blank

hard

Fill both blanks to create an array of 3 strings and assign a value to the second element.

Go

[1] fruits [3]string
fruits[[2]] = "Apple"

Drag options to blanks, or click blank then click option'

Avar

B0

C1

Darray

Attempts:

3 left

💡 Hint

Common Mistakes

Using 0 instead of 1 for the second element

Using array keyword which is not valid in Go

To declare an array in Go, use var followed by the variable name and type. The second element of an array is at index 1 because indexing starts at 0.

5fill in blank

hard

Fill all three blanks to create an array, assign values, and print the last element.

Go

[1] scores [4]int
scores[0] = 90
scores[[2]] = 85
fmt.Println(scores[[3]])

Drag options to blanks, or click blank then click option'

Avar

B3

C1

Darray

Attempts:

3 left

💡 Hint

Common Mistakes

Using 4 as an index which is out of range

Using array keyword instead of var

Declare the array with var. The second assignment is to index 1 (second element). The last element in an array of size 4 is at index 3.